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Typical systems will deliver roughly 10 to 12% of their rated power. 50 kWh divided by 24 hours in a day means the system will need to produce slightly over 2 kWh each hour. Assuming the 10% efficiency, we will need to specify a 20kWh unit in order to average 50 kWh each day.

There will be other losses in the total system including losses in the inverter and line loss. Slightly over specing the system is a good idea.

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Q: How big should a wind mill be to produce 50kWh per day?
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