p.f=kW/kV.A
Power Factor = KVA/KW. This has no unit. Its value is always 1 or less.
If a load takes 50 kW at a power factor of 0.5 lagging calculate the apparent power and reactive power Answer: Apparent power = Active power / Power Factor In this case, Active power = 50 kW and power factor = 0.5 So Apparent power = 50/0.5 = 100 KVA
The 0.8 Power Factor provided by generator manufacturers is not the load power factor, but it is the nominal power factor used to calculate the kW output of an engine to supply the power for a particular alternator kVA output. Alternators are therefore designed to supply their rated kVA at 0.8 lagging power factor.
in case of inductor or capacitor power factor is always zero.as power factor is cosine of phase angle between voltage and current. in case of inductor and capacitor phase angle between voltage and current is 90 so it become zero so if given power factor is zero then it can be inductor or capacitor.
If you multiply kVA by Power Factor (Ranges from zero to one) you get watts which is effective power.
simply by measuring the coil voltage, coil current & power factor.
To calculate the power factor (pf) of a 1010 kVA diesel generator (DG) set, you can use the formula: [ \text{Power Factor (pf)} = \frac{\text{Real Power (kW)}}{\text{Apparent Power (kVA)}} ] First, determine the real power (kW) output of the DG set, which can be obtained from the manufacturer's specifications or by measuring the actual load. Then, divide the real power by the apparent power (1010 kVA) to find the power factor. Typically, a power factor of 0.8 to 0.9 is common for DG sets.
Amps = Watts / (Volts x Power Factor). The Power Factor is one for resistive loads and decreases for inductive loads like motors.
Rephrase your question so that it makes sense.
LPF is Low power factor, which is used to calculate overall power in VA (voltamps) kind of like calculating overall power in watts.
To calculate three-phase power with a power factor, you would use the formula: P = √3 x V x I x PF, where P is power in watts, V is voltage, I is current, and PF is the power factor. Multiply √3 (1.732) by the voltage, current, and power factor to determine the power in watts.
1 HP is 746 watts in principle. The power is in watts, and the power is the volts times the amps. For an AC motor the power is the volts times the amps times the power factor times a factor that depends on the power-conversion efficiency of the motor.