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How can I calculate the energy of a photon if I know the wavelength?
Wiki User
∙ 14y ago
Multiply (Planck's constant) times (the speed of light), and divide the result by the photon's wavelength.
Be careful to keep the units consistent.
Wiki User
∙ 14y ago
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How do you find the energy of a photon?
You need to know the photon's frequency or wavelength. If you know the wavelength, divide the speed of light by the photon's wavelength to find the frequency. Once you have the photon's frequency, multiply that by Planck's Konstant. The product is the photon's energy.
How do you find wavelength if you've been given the energy?
The easiest way would be to find a descriptive article on the internet that shows the visible colors spread out with some wavelengths labeled. There, you can find the approximate wavelengths for light of various colors. If you don't know the color of the light, then in order to find its wavelength, you'd need to know either its frequency or the energy of a photon (quantum). Energy of a photon = h f h = Planck's Konstant = about 6.63 x 10-34 joule-second f = frequency of the light wave or photon But the frequency is (speed of light)/(wavelength) so, Energy = h c/wavelength . If you know either the energy of the photon or its frequency, you can use this stuff to find its wavelength. In this discussion, I've toggled back and forth a few times between the frequency/wavelength of the quantum and the frequency/wavelength of the light wave. Don't worry. They're the same.
What is the energy of a photon?
the energy of a photon is h times f
Describe the relationship between the wavelength and it's energy?
c is the speed of sound or the speed of light. You must know what you need. There is a relationship between the wavelength lambda and the frequency f. But forget the energy! c= lambda times f f is proportional to 1 / lambda. f = c / lambda lambda = c / f
If you know the wavelength of an electromagnetic wave in a vacuum you can calculate its?
Momentum, energy, frequency, and wave number (but not wave vector.)
How do you find the energy of a photon?
You need to know the photon's frequency or wavelength. If you know the wavelength, divide the speed of light by the photon's wavelength to find the frequency. Once you have the photon's frequency, multiply that by Planck's Konstant. The product is the photon's energy.
What is the energy of a photon?
the energy of a photon is h times f
How do you find wavelength if you've been given the energy?
The easiest way would be to find a descriptive article on the internet that shows the visible colors spread out with some wavelengths labeled. There, you can find the approximate wavelengths for light of various colors. If you don't know the color of the light, then in order to find its wavelength, you'd need to know either its frequency or the energy of a photon (quantum). Energy of a photon = h f h = Planck's Konstant = about 6.63 x 10-34 joule-second f = frequency of the light wave or photon But the frequency is (speed of light)/(wavelength) so, Energy = h c/wavelength . If you know either the energy of the photon or its frequency, you can use this stuff to find its wavelength. In this discussion, I've toggled back and forth a few times between the frequency/wavelength of the quantum and the frequency/wavelength of the light wave. Don't worry. They're the same.
Describe the relationship between the wavelength and it's energy?
c is the speed of sound or the speed of light. You must know what you need. There is a relationship between the wavelength lambda and the frequency f. But forget the energy! c= lambda times f f is proportional to 1 / lambda. f = c / lambda lambda = c / f
If you know the wavelength of an electromagnetic wave in a vacuum you can calculate its?
Momentum, energy, frequency, and wave number (but not wave vector.)
What are the frequency and wavelength of a photon which jumped from energy level 5 to energy level 2?
Use this formula to find frequency. Frequency (Hertz) = (3.29 X 10^15 Hz)*Z^2*(1/nf^2 - 1/ni^2) use this to find wavelength Wavelength = speed of light/frequency in Hz Now, you need to know what the Z number (atomic number-Carbon = 6, for instance ) is of the element that generated the photon of light.
How do you calculate energy per mole of photons if you know joules per photon?
You have to multiply the joules/photon by Avogadro's Number, i.e., by the number of particles in a mole.
A typical wavelength of infrared radiation emitted by your body is 25 micrometers. What is the energy per photon of such radiation?
* E = hf = hc/wavelength = (6.63 x 10-34 J*s)(3.00 x 108 m/s)/(25 x 10-6 m) = 7.9 x 10-21 J per photon. This is the energy of a photon at that wavelength. == The person who asked the question answered it. Why ask a question to which you already know the answer? And the body under "normal" conditions radiates infrared (IR) most strongly at about 10 micrometers.
A photon has a wavelength 624 nm. Calculate the energy of the photon in joules.?
You know that,E = h*c/λWhereh = Plank's constant = 6,626 x 10-34 J*sc = speed of light = 3*108 m/sλ = greek letter lambda representing the wavelength =624nm => 6,24 *10-7mand therefore [(6.626 X 10^-34 J) X (3 X 10^8 m/s)] / (6.24 x 10^-7) = 3.18 x 10^-19 ... That should be right!
How can gravity affect a photon's path when a photon is massless?
The photon is only massless when it's at rest. But it's never at rest ... it's always moving at the speed of light, and at that speed, it has mass. How much mass ? Easy to calculate! (Maybe meaningless, but easy to calculate.) We can easily find the energy of the photon, because it's simply (frequency of the radiation) times (Planck's Konstant). The photon's energy is all kinetic energy, which we know is [ 1/2 M V2 ], and 'V' is always ' c '. So there you are! If you know the frequency (or wavelength) of the radiation, then the mass of the photon practically falls right out, onto the floor. It's [ 2 h (freq)/c2 ] . By the way, speaking of weird stuff, I skipped over the part along the way where the photon's energy is all kinetic energy . . . [ E = 1/2 M V2 ] but the photon's 'V' is always ' c ', so [ E = 1/2 M c2 ] . Does this remind us of any other little equation we've seen before ? Except for that factor of 1/2 , they're both the same equation. What is the connection, and what is going on ? I have no idea.
Which of the following can be determined from the frequency of a light wave?
If you know the frequency of a light wave, you can tell the wavelength, thecolor it'll appear to your eye, and the energy in each photon of the light.The energy of the wave ~APEX
How do you calculate the amplitude given the frequency and the wavelength?
Amplitude doesn't depend on frequency or wavelength, so even if you know them, you have no way to calculate amplitude.
