a 22yr old in only 10a your tiny
9
To multiply m x 10a by n x 10b: multiply the numbers (m x n) add the powers (a + b) (m x 10a) x (n x 10b) = mn x 10a+b To divide m x 10a by n x 10b: divide the numbers (m / n) subtract the powers (a - b) (m x 10a) / (n x 10b) = m/n x 10a-b
Nope. Perfectly normal, 10B/8B. I'm the same size!
yes that is a good size
Not for a 15 year old.
13
The number is 34 a + b = 7 a = 7 − b 10a + b + 9 = 10b + a 10(7 − b) + b + 9 = 10b + 7 − b 70 − 10b + b + 9 = 9b + 7 72 = 18b 4 = b 3 = a
Isaiah's father, Amotz, was the brother of King Amatziah (Talmud, Megillah 10b). Isaiah's daughter married King Hizkiah (Talmud Berakhot 10a), and Isaiah's grandson was Menashe.
They are considered a triple combination. Or called a "3 jump effort". Example:jump #10 is a triple, a three jump effort and will be numbered as such:#10a, #10b, #10c
10b
If it's a one-digit number then any 1-digit number will do (0...9) 2-digits numbers : ab=10a+b=a+b it's not possible unless a=0 For 3-digits: abc=100a+10b+c=a+b+c => 100a+10b = a+b it' not possible unless a=b=0 And so on...
f = 10a + b so s = a + 10b; f - 1 = 2(s - 1) so f = 2s - 2 + 1 ie 2s - 1 ie 10a + b = 2a + 20b - 1 8a = 19b - 1, making a = 7 and b = 3. So Father is 73 and son is 37. (Last year f = 72, s = 36)