It cannot be. The cardinality of the set of real numbers is the Continuum. This is greater than the total number of sub-atomic particles in the universe!
5 6356 5463 34 6 That is just not true. Real numbers do not include complex numbers, that is, those that include the square root of -1, for example.
By its very name .. it is UNDEFINED. Even in the Extended Real Number set containing +-infinity these elements are UNDEFINED.
Subtraction is definitely an operation defined on real numbers. I'm guessing you are actually asking why subtraction is not included as a commutative operation, this is because a-b is not always equal to b-a.
Rational numbers and Real Numbers. The multiplicative inverses of integers are not integers.
The grouping in which the numbers are taken does not affect the sum or product.
Real numbers include both positive and negative numbers, and also zero; also included are integers and fractions, including all types of fractions (rational, irrational, or transcendental). Only imaginary numbers are not real.
Infinite
It's a set with an infinite quantity of elements, like the set of all real numbers, or the set of all real numbers except zero, etc.
Yes. Anything that can be put on the number line is real. You will learn about imaginary and complex numbers in advanced math. They are included in complex numbers but again that is very advanced math.
-54 is included in negative integer or rational nos.
Many options - e.g. -2"Real number" means all the numbers we know, including positive and negative numbers.The only numbers that are not included are "imaginary numbers" - numbers that have an imaginary part i (used only i physics or high mathematics).See real-number
An irrational number is included in the Venn diagram of real numbers. The subsets of the set of the real numbers are: The set of all natural numbers, N; the set of all whole numbers, W; the set of all integers, I; the set of all rational numbers, Q; and the set of all irrational numbers, S. It is obvious that N is a subset of W, W is a subset of I, and I is a subset of Q, but similar relationship doesn't hold between Q and S. However, this fact does not mean that irrational numbers are not in the Venn diagram, because they are also real numbers as well.