Dissolve 16,61 g NaCl analytical reagent, dried in 1 L of demineralized water at 20 0C, in a volumetric flask.
To prepare a 1 liter of 100ppm NaCl solution, you would dissolve 0.1 grams of NaCl in 1 liter of water. This concentration is achieved by mixing 0.1 grams of NaCl in 1 liter of water.
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.
By a slowly evaporation of water from a NaCl solution.
To prepare a 2% NaCl (w/v) solution, you would dissolve 2 grams of NaCl in enough water to make 100 mL of solution. This means you would add 2 grams of NaCl to a flask and then add water until the total volume reaches 100 mL.
You have to evaporate (by open boiling) 45 mL of the 75 mL 2M NaCl solution thus reducing the volume to 30 mL 5M NaCl.
We first calculate the amount, in moles, of NaCl that we will need.Amount of NaCl needed = 0.24 x 400/100 = 0.096mol. Mass of NaCl needed = (23.0 + 35.5) x 0.096 = 5.616g So to produce 400ml of 0.24M NaCl solution, accurately add 5.616 grams of NaCl to 400ml of deionised water.
Reactions are: 2Na + Cl2 = 2NaCl NaOH + HCl = NaCl + H2O
Sodium chloride is the result of this reaction: NaOH + HCl = NaCl + H2O
A method is the following:NH4Cl + NaNO2 = N2 + NaCl + 2 H2O
To prepare 100 ml of 1.0 M NaCl solution, you would need to dissolve 5.84 g of NaCl in enough water to reach a final volume of 100 ml. Measure out the required amount of NaCl, add it to a beaker, and then add water while stirring until the final volume reaches 100 ml.
Two reactions, for example: 2Na + Cl2 = 2NaCl NaOH + HCl = NaCl + H2O