2Al + 3Cl2 ---> 2AlCl3
2Fe+3Cl2------>2FeCl3
So you have 3 Cl on the left and 2cl on the right. First off you put a 2 in front of the AlCl3 to give you 6 Cl, and you put a 3 in front of the MgCl2 to also give you 6Cl on the right side. You then have to balance the Mg and Al, so put a 3 in front of the Mg on the left to give you 3Mg, and 2 in front of the Al on the right to give you 2Al. Your final, balanced formula is 3Mg + 2AlCl3 => 3MgCl2 + 2Al
2Al + 2HCl ---> AlCl3 + 5H2 To balance it, just make the different atoms on each side equal eachother. For example, there are 2 Al atoms on the left side. Therefore 2 Al atoms must be on the right side as well. Put a 2 in front of AlCl3. Now, you look at the Cl atoms. Because you multiplied AlCl3 by 2, you have 6 chlorine atoms (2 x 3 = 6) on the right side. So you must have 6 chlorine atoms on the left side. Multiply HCl by 6. Now, you've balanced the Al and Cl atoms. Now all you have to do is balance the H atoms and you're done. On the left side, you multiplied HCl by 6, so you must have 6 H atoms on the right side. multiply H2 by 3 (3x2 = 6) to get 6 H atoms on the right side. Now you're done. Your final balanced equation looks like this: 2Al + 6HCl ---> 2AlCl3 +3H2
Correctly written it is 2Al(s) + 3Cl2(g) = 2AlCl3(s)
HCl + Al2O3 ----- H2O + AlCl3 H 1 Cl 1 Al 2 O 3 6HCl + Al2O3 --------- 3H2O + 2AlCl3
KOH + NH4CL - KCL + NH3 + H2O = N = OOH + NH4CL - CL + NH3 + H2OO + N4CL - CL + N3 + 2ON4CL - CL + N3 + ON4 - N3 + ON = OBut would only work if you are on about maths, algebrabtw im only 13
The electrolysis of molten aluminum chloride involves the migration of Al3+ and Cl- ions to the respective electrodes. At the cathode, aluminum ions are reduced to form aluminum metal, while at the anode, chloride ions are oxidized to form chlorine gas. The overall reaction can be represented as 2Al3+ + 6e- -> 2Al (reduction at cathode) and 2Cl- -> Cl2 + 2e- (oxidation at anode).
It is already balanced, you have the same number of H's and the same number of Cl's in each side of the equation.
Na+ and Cl- are spectator ions.
The reaction is already balanced as it is written: Cl₂ + 2Kl → 2KCl + Cl₂. Each side of the reaction has the same number of atoms for each element.
2Na + 2H2O = 2NaOH + H2 2Na + 2HCl = 2NaCl + H2 Na+H2O= NaOH2
The balanced chemical equation for the reaction between magnesium (Mg) and chlorine (Cl) to form magnesium chloride (MgCl2) is: 2Mg + Cl2 → 2MgCl