2Al + 3Cl2 ---> 2AlCl3
2Fe+3Cl2------>2FeCl3
KOH + NH4CL - KCL + NH3 + H2O = N = OOH + NH4CL - CL + NH3 + H2OO + N4CL - CL + N3 + 2ON4CL - CL + N3 + ON4 - N3 + ON = OBut would only work if you are on about maths, algebrabtw im only 13
So you have 3 Cl on the left and 2cl on the right. First off you put a 2 in front of the AlCl3 to give you 6 Cl, and you put a 3 in front of the MgCl2 to also give you 6Cl on the right side. You then have to balance the Mg and Al, so put a 3 in front of the Mg on the left to give you 3Mg, and 2 in front of the Al on the right to give you 2Al. Your final, balanced formula is 3Mg + 2AlCl3 => 3MgCl2 + 2Al
2Al + 6HCl = 2Al(Cl)3 + 3H2
HCl + Al2O3 ----- H2O + AlCl3 H 1 Cl 1 Al 2 O 3 6HCl + Al2O3 --------- 3H2O + 2AlCl3
MgCl2
2Al + 2HCl ---> AlCl3 + 5H2 To balance it, just make the different atoms on each side equal eachother. For example, there are 2 Al atoms on the left side. Therefore 2 Al atoms must be on the right side as well. Put a 2 in front of AlCl3. Now, you look at the Cl atoms. Because you multiplied AlCl3 by 2, you have 6 chlorine atoms (2 x 3 = 6) on the right side. So you must have 6 chlorine atoms on the left side. Multiply HCl by 6. Now, you've balanced the Al and Cl atoms. Now all you have to do is balance the H atoms and you're done. On the left side, you multiplied HCl by 6, so you must have 6 H atoms on the right side. multiply H2 by 3 (3x2 = 6) to get 6 H atoms on the right side. Now you're done. Your final balanced equation looks like this: 2Al + 6HCl ---> 2AlCl3 +3H2
It is already balanced, you have the same number of H's and the same number of Cl's in each side of the equation.
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Na+ and Cl- are spectator ions.
Al(s) + MgCl2(aq) ==> no reaction or a very slow reaction. The reason being that Mg is more reactive than Al so Al will not readily displace/replace Mg. If the reaction occurs, it will be 2Al(s) + 3MgCl2(aq) ==> 2AlCl3(aq) + 3Mg(s)
The chemical equation is:2 Al +3 CuCl2 = 3 Cu + 2 AlCl3