2nh4no3 ---> 2n2 + o2 + 4h2o
it does not produce N2, it produces NO. i think this will help you to balance your equation well in the problem i have, i got: 4 NH3(g) + 3 O2(g) yields 2 N2(g) + 6 H2O(g) No N2 will be produce... This will only produce NO and H2O the balanced equation is 4NH3 + 5O2 --> 4NO + 6H2O this is an equilibrium reaction.
Yes: 2 NH4NO3 = 2 N2 + 4 H2 + 3 O2.
NH4NO2 yields N2 + 2H2O
No, it's not balanced because the number of hydrogens and nitrogens on the left is not equal to the number on the right. 3H2 + N2 --> 2NH3
Mn is for manganese I think. Ok first of all check the number of molecules on each side. on the left, Mn has 1, Oxygen has 2, Nitrogen has 1, Hydrogen has 4. On the right hand, Mn has 2,Oxygen has 3, nitrogen has 1 and Hydrogen has 5. all need to be balanced.So the resulting coefficients on both sides should be;2(MnO2) + 2(NH4) --- > Mn2O3 + 2(NH3) + H2O
First make the reaction equation balanced for N-atoms (co-existant in both formula)N2O5 + H2O --> 2 HNO3So 1.02 mole HNO3 is produced from:1.02 x 1 (N per HNO3) / 2 (N per N2O5) = 0.51 mol N2O5
Well 6Na + N2 > 2Na3N
no
NH4NO2(s) --Δ--> 2 H2O(l) + N2(g)
Four ammonia plus five oxygen molecules yields 4 nitrous oxide plus six water.
Nh4no2----n2+2h2o
The balanced equation would be 2N2H4 + N2O4 = 3N2 +4H2O
nh4no2=n2+2h2o Should be all Caps. Im not sure how to do this.
2NH4NO3->2N2+O2+4H2O
The balanced reaction for N2H4 + H2O2 --> N2 + H2O is N2H4 + 2H2O2 --> N2 + 4H2O
3H2 + N2 yields 2NH3
N2
co2 and h2o
H2O, CO2, N2, O2, C6H11O6 H2O, CO2, N2, O2, C6H11O6
N2 + o2 = no2