Four ammonia plus five oxygen molecules yields 4 nitrous oxide plus six water.
First you have to balance the equation N2 + H2 ---> NH3 N2 +3H2 ---> 2NH3 Then you have to use the Molecular Weight and number of mols required for complete reaction of each one to go from 14g N2 + xg of H2 to get the final result.
To determine the limiting reactant, first convert the masses of N2 and H2 to moles. Then divide the amount of each reactant by its stoichiometric coefficient in the balanced equation to find moles of NH3 produced. The limiting reactant is the one that produces the least amount of NH3.
To balance the equation Zn + HCl → ZnCl2 + H2, you need to ensure that the number of each type of atom is the same on both sides of the equation. To balance it, you would need to write it as Zn + 2HCl → ZnCl2 + H2. This equation balances the number of zinc, hydrogen, and chlorine atoms on both sides.
To balance the equation CO2 + H2 ➝ CH3OH, you would need to first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation would be: CO2 + 3H2 ➝ CH3OH + H2O.
In the reaction N2 + 3H2 → 2NH3, nitrogen (N2) is reduced because it gains hydrogen atoms, and hydrogen (H2) is oxidized because it loses electrons.
(N2) + 3(H2) = 2(NH3)
The formula for the synthesis of ammonia from diatomic nitrogen and hydrogen is: N2+3H2-->2NH3
This is a synthesis reaction.
The expression n2 + h2 + nh3 is the sum of the squares of two numbers n^2 and h^2, along with the product of n and h multiplied by 3.
You can make a simple balance. There are (12.36 * 3) moles of H You have 2*H to form H2. So take the total from ammonia and divide by two to find the moles of H2 required.
H2 - hydrogen.
2Na + 2H2O -> H2 + 2NaOH
16,45 g nitrogen are needed.
2Na + 2H2O -------> 2NaOH + H2
Yep
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.