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How do you balance N2 H2NH3?
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What is the maximum amount of NH3 gas formed by mixing of 14 g N2 and 6 g H2 gases is?
N2(g) + 3H2(g) ==> 2NH3(g) is the balanced equation for this reaction.14 g N2 x 1 mole N2/28 g = 0.5 moles N2 present 6 g H2 x 1 mole H2/2 g = 3 moles O2 present In this situation, the amount of N2 is limiting the overall reaction. So, the maximum amount of NH3 that can be produced will be limited by the amount of N2. 0.5 moles N2 x 2 moles NH3/1 mole N2 = 1 moles NH3 is the maximum amount of NH3.
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