First you have to balance the equation
N2 + H2 ---> NH3
N2 +3H2 ---> 2NH3
Then you have to use the Molecular Weight and number of mols required for complete reaction of each one to go from 14g N2 + xg of H2 to get the final result.
To find the mass of nitrogen needed to make ammonia, first determine the molar mass of ammonia (NH3) which is 17 g/mol. Since there is one nitrogen atom in ammonia, the nitrogen mass is 14 g/mol. To make 34 grams of ammonia, you would need 14 grams of nitrogen.
Assuming you mean the decomposition of ammonia: 2NH3 --> N2 + 3H2, 100g NH3 = 5.88mol (100/17), and the ratio of ammonia to nitrogen is 2:1. 5.88mol/2=2.94mol, so that's the amount of nitrogen produced. 2.94x28 (molar mass of N2) gets you 82.3g nitrogen produced.
To find the number of moles in 1200 grams of ammonia, divide the given mass by the molar mass of ammonia. The molar mass of ammonia (NH3) is approximately 17 grams/mole. Therefore, 1200 grams divided by 17 grams/mole equals approximately 70.59 moles of ammonia.
(34 g NH3) x (14 g N ) / (17 g NH3) = 28 g N(28 g N) x (1 g N) / (2 g N2) = 14 g N2
36.084g/mol is INcorrect1*14.01 + 4*1.008 = 18.042 g/mol for NH4, but this is not an exsiting compound.Ammonia is NH3 (17.034), ammonium is NH4+(18.042).
nitrogen weighs 14, hydrogen weighs 1, so NH3 weighs 14+(3x1)=17grams
You can find the mass of one mole of each of the individual elements by looking at the mass numbers.So, 1 mole of:N=14gH=1gsince there are 3 H's the total mass of 1 mole NH3 is 14+3=17gYou then multiply the actual number of moles by the g's per mole:=> 17x2.11=35.87g
To find the mass of nitrogen needed to make ammonia, first determine the molar mass of ammonia (NH3) which is 17 g/mol. Since there is one nitrogen atom in ammonia, the nitrogen mass is 14 g/mol. To make 34 grams of ammonia, you would need 14 grams of nitrogen.
the molecular mass number of NH3 = 17 atomic mass no.of N=14 x 1 atom (present in the compound)=14 atomic mass of H= 1 x 3 atoms (present in compound)=3 thus, molecular mass= atomic mass of N+ atomic mass of H3 = 14 + 3 = 17
The molecular mass of NH3 is the sum of the atomic mass of nitrogen and three times the atomic mass of hydrogen, or 14.007 + 3(1.008) = 17.031. Therefore, the number of moles of NH3 in 14.0 grams is 14.007/17.031 = 0.822. Since each molecule of N2 supplies two nitrogen atoms and each molecule of NH3 needs only one nitrogen atom, the number of moles of N2 needed is half the number of moles of NH3 formed = 0.411.
0.545 * (14+1+1+1) 0.545 * ram n + 3 * ram h
14 grams of palm oil is about a half of an ounce if that helps.
It is 14 - 3 = 11 grams more massive.
75
14 grams
NH3, or ammonia, has a molar mass of 17.031 g/mol. So .500 moles of the substance would equal 8.5155 grams.
14 oz of caster sugar is equivalent to ~397 grams of it.