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First you have to balance the equation
N2 + H2 ---> NH3
N2 +3H2 ---> 2NH3
Then you have to use the Molecular Weight and number of mols required for complete reaction of each one to go from 14g N2 + xg of H2 to get the final result.
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∙ 15y ago
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How many grams of nitrogen gas are needed to make 34 g of ammonia?
(34 g NH3) x (14 g N ) / (17 g NH3) = 28 g N(28 g N) x (1 g N) / (2 g N2) = 14 g N2
What number of grams of NH3 produced by the reaction of 3.5g of hydrogen gas with sufficient nitrogen gas?
Assuming you mean the decomposition of ammonia: 2NH3 --> N2 + 3H2, 100g NH3 = 5.88mol (100/17), and the ratio of ammonia to nitrogen is 2:1. 5.88mol/2=2.94mol, so that's the amount of nitrogen produced. 2.94x28 (molar mass of N2) gets you 82.3g nitrogen produced.
How many nitrogen in NH3?
You are probably asking about the molar mass of NH3. This is a measure of the amount of grams in one mole of NH3. This can be found by adding the molar masses of each element. Also, you must be sure to multiply each molar mass of an element by the number of atoms of that element that are present. In NH3 there is one nitrogen atom and 3 hydrogen atoms. Nitrogen has a molar mass of 14.01 and Hydrogen has a molar mass of 1.008. Therefore: 1*(14.01) + 3*(1.008) = 17.034 So for every mole of NH3 you will have 17.034 grams.
How many atoms make up 1 molecule of ammonia?
Ammonia = NH3 and has a molar mass of 17.031 g/molmoles NH3 = 63.9 g x 1 mol/17.031 g = 3.752 molesmolecules NH3 = 3.752 moles x 6.02x10^23 molecules/mole = 2.259x10^24 moleculesEach molecule of NH3 has 4 atoms (1 N + 3 H), thus....number of atoms = 4 atoms/molecule x 2.259x10^24 molecules = 9.04x10^24 atoms (to 3 sig figs)
How many moles of nitrogen gas are there in 35.7 gm of nitrogen gas?
molar weight of N = 14 grams/mole 35.7 grams/14 grams/mole = 2.55 moles
Calculate mass in grams of 2.110 moles of NH3?
You can find the mass of one mole of each of the individual elements by looking at the mass numbers.So, 1 mole of:N=14gH=1gsince there are 3 H's the total mass of 1 mole NH3 is 14+3=17gYou then multiply the actual number of moles by the g's per mole:=> 17x2.11=35.87g
How much does a mole of nh3 weigh?
nitrogen weighs 14, hydrogen weighs 1, so NH3 weighs 14+(3x1)=17grams
How many grams of nitrogen gas are needed to make 34 g of ammonia?
(34 g NH3) x (14 g N ) / (17 g NH3) = 28 g N(28 g N) x (1 g N) / (2 g N2) = 14 g N2
What is the weight of 0.545 mol of NH3 in grams?
0.545 * (14+1+1+1) 0.545 * ram n + 3 * ram h
How many gram of f2 are required to react with 3.50 moles of nh3?
The reaction equation is 8 F2 + 2 NH3 equals N2F4 + 6 HF2. So every mole of NH3 requires four moles of F2. This means 14 moles of F2 or 532 grams.
How many moles of NH3 can be produced from 14 grams of N2?
The molecular mass of NH3 is the sum of the atomic mass of nitrogen and three times the atomic mass of hydrogen, or 14.007 + 3(1.008) = 17.031. Therefore, the number of moles of NH3 in 14.0 grams is 14.007/17.031 = 0.822. Since each molecule of N2 supplies two nitrogen atoms and each molecule of NH3 needs only one nitrogen atom, the number of moles of N2 needed is half the number of moles of NH3 formed = 0.411.
How much is 14 grams of palm oil?
14 grams of palm oil is about a half of an ounce if that helps.
What is the mass of 0.500 mol of NH3?
NH3, or ammonia, has a molar mass of 17.031 g/mol. So .500 moles of the substance would equal 8.5155 grams.
How much more massive is 14 grams of nitrogen than an 3 grams of nitrogen?
It is 14 - 3 = 11 grams more massive.
How much is a miliounce of gold?
14 grams
How much is 14 grams worth?
75
How much is 14 oz caster sugar in grams?
14 oz of caster sugar is equivalent to ~397 grams of it.
