You will need a media gateway in order to connect a GSM network to PSTN lines without the need for a PBX or key system.
Connect the two inputs of the NAND gate together.
the easiest way to make an xnor gate is with a 7486 (or equivalent) integrated circuit, a quad xor gate. connect the output of one gate to one in put of another gate. connect the other input of the second gate to Vcc. the second xor gate will then act as an inverter.
The Golden Gate Bridge was needed so, the two sides of the bay will connect.
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Yes, but only if its output is logically inverted (a AND gate's behavior is a direct opposite of a NAND gate's behavior, logically).
Yes. Its A DIRECT NAME.
Assume that the two inputs of the XOR gate are I1 and I2, and that the two inputs of the multiplexer are M1 and M2 and the selection line is S: Connect I1 to M1 Connect Not(I1) to M2 Connect I2 to S
You would connect the output of the first AND gate to one input of the second AND gate. You are left with 2 inputs on the first AND gate and 1 input on the second AND gate. The final output is from the second AND gate.
This is a state that disconnects the gate from the line it drives so that another gate can connect to it and drive it instead. This permits sharing so that multiple sources can drive common lines without fighting and/or damaging each other.
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yes (a or b)' = a' and b' a or b = (a' and b')' a or b = a' nand b'
A: Without the gate there is only two diodes back to back. The gate is the turn on switch