If you have two numbers, multiply them together and divide that total by the GCF. The result will be the LCM.
Without a specific number, all of the numbers in that range are multiples.
We won't be able to answer that without knowing the numbers.
By finding their common prime numbers.
No. A factor is a number or algebraic expression by which another is exactly divisible. A multiple is a number that can be divided by another number without a remainder. Factors go into numbers, numbers go into multiples.
There is not a greatest common factor of 70 because there cannot be a greatest common factor without two or more numbers to compare. Common factors are factors that the numbers being compared have in common.The factors of 70 are 1, 2, 5, 7, 10, 14, 35, and 70.You need at least two numbers to find a GCF.
The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three. The infinite set of numbers which are multiples of three.
They are numbers that each of the two numbers can divide without remainder.
Numbers that can be divided by other numbers without a remainder.
They are the 3333 numbers that are divisible by 3 without remainder.
Without a specific number, all of the numbers in that range are multiples.
We won't be able to answer that without knowing the numbers.
By finding their common prime numbers.
Difficult to answer without knowing the numbers below. Choose multiples of 4. They will be even numbers.
#include<stdio.h> #include<conio.h> void main() { int i, a[100]; clrscr(); printf("Numbers from 1 to 100"); for(i=1;i<=100;i++) printf(" %d",a[i]); printf("Numbers from 1 to 100 without multiples of 2"); for(i=1;i<=100;i++) { if (a[i]%2 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 3"); for(i=1;i<=100;i++) { if (a[i]%3 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 4"); for(i=1;i<=100;i++) { if (a[i]%4 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 5"); for(i=1;i<=100;i++) { if (a[i]%5 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 6"); for(i=1;i<=100;i++) { if (a[i]%6 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 7"); for(i=1;i<=100;i++) { if (a[i]%7 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 8"); for(i=1;i<=100;i++) { if (a[i]%8 !=0) printf(" %d",a[i]); } printf("Numbers from 1 to 100 without multiples of 9"); for(i=1;i<=100;i++) { if (a[i]%9 !=0) printf(" %d",a[i]); } getch(); }
This will be difficult to answer accurately without knowing each set of numbers.
We can't answer that without knowing the numbers. The first five multiples of 5 are 5, 10, 15, 20 and 25.
A number that can be divided by another number without a remainder.