Here are some examples:
In the word "function" you have 8 letters. 6 different letters and 2 equal letters.The number of different arrangements that are possible to get are:6!∙8C2 = 720∙(28) = 20 160 different arrangements.
there are 36 different combination possibilities. Try them all.
10!/(2!2!2!)=Answer 10 being 10 letters There are "2" c's, a's, and l's, so you must divide those factorials with the total number. Answer = 7257600
There are 5 letters: a c e f and h.If the letters can be repeated, then there are five possibilities for each space in the four-letter arrangement. The number of arrangements then is:5*5*5*5 = 54 = 625.
Since any two letters of the alphabet do not duplicate each other, then the number of arrangements of any two letters is the same as the number of permutations of 26 things taken 2 at a time. That is 26! / (26 - 2)!, or 26! / 24!, or (26) (25), or 650.
6! = 6x5x4x3x2x1 = 720 arrangements
In the word "function" you have 8 letters. 6 different letters and 2 equal letters.The number of different arrangements that are possible to get are:6!∙8C2 = 720∙(28) = 20 160 different arrangements.
5! 5 * 4 * 3 * 2 *1 = 120 arrangements you take the number of letters in the words and make it a factorial.
The number of arrangements of the letters PARTY, if the first letter must be an A is the same as the number of arrangements of the letters PRTY, and that is 4 factorial, or 24.
there are 36 different combination possibilities. Try them all.
The number of different three letter arrangements that can be done from theletters in the word "mathematics"is; 11P3 =11!/(11-3)! =990
The number of 5 letter arrangements of the letters in the word DANNY is the same as the number of permutations of 5 things taken 5 at a time, which is 120. However, since the letter N is repeated once, the number of distinct permutations is one half of that, or 60.
When trying to work out how many different combinations there are, you need to know how many options there are for each value. If the password only contains lower case letters, then we have 26 options for each value. For each letter in the password, there are 26 options, so the total number of possible options is 26x26x26x26x26x26 or 266 This equals 308,915,776 so there are 308,915,776 possible different combinations of six letters.
The number of distinct arrangements of the letters of the word BOXING is the same as the number of permutations of 6 things taken 6 at a time. This is 6 factorial, which is 720. Since there are no duplicated letters in the word, there is no need to divide by any factor.
If you pick from each of the possible letters at each stage, then there are 5 possible options for the first letter. Then there are 4 possible options for the second. Then there are 3 possible options for the 3rd and so on. This leaves us with 5x4x3x2 = 120 different arrangements. However, each arrangement has been counted twice, as it doesn't matter which way around the Os go. So to get the true answer, we need to divide by 2. 120/2 = 60, and therefore the number of different arrangements of the letters in the word COLOR is 60.
Take note of the word "surprising":There are 10 letters total.There are 2 r's.There are 2 i'sThere are 2 s's.There are 10! total ways to arrange the letters. Since repetition is not allowed for the arrangements, we need to divide the total number of arrangements by 2!2!2! Therefore, you should get 10!/(2!2!2!) distinct arrangements
40, the amount of letters in the word, 5, times the number of letters subtracted by one, 4, times the number of letters in the new combination, 2.