pivot 4 does not exist. try visiting the david bone site and youll get some info kaiakai says na da to that its wrong it existests a freind has it and its free ware enfisise on 'free'
If you used to pay 40, but now you're paying 30,you're paying 25% less now than you were before.I wouldn't say that you're "saving" anything, becauseyou're still paying 30 .
If you're paying my bill, I'll save 100 percent. 30 is 25% less than 40
40 inches long for a short stick including the head
Take your knife, tilt it at a 40 degree angle lay it on the stick and push it away from your body.
a jumbo candle stick from target.
Buy it at the 7/11 store
£50000000000000000000000000000000000000 because you don't have the sence to go onto a pogo stick sales website
Your set-up is so long that that you ran out of space before you could ask thequestion. In fact, you got cut off leaving us with two questions . . . howheavy should a single weight be, and where should it hang, in order to balancethe whole thing ?I just noticed that since the stick is 1 meter long, and the three originalweights are placed at the 10cm, 40cm, and 60cm marks, the 10 and the40 are on one side of the pivot, and the 60 is on the other side, 10 cmfrom the pivot. It's all starting to come together.On one side:-- There is a weight at the "10cm" mark. That point is 40 cm from the pivot,and the weight is 100N, so the moment pulling this side down is 4,000 N-cm.-- There is another weight at the "40cm" mark, and that's 10cm from the pivot.The weight is 150N, giving us another 1,500 N-cm pulloing this side down.-- The total moment pulling this side down is (4,000 + 1,500) = 5,500 N-cm.-- (Plus another 25 x 100 = 5,000 due to the weight of 1/2 the stick. But theother half is already balancing that much, so I don't think we need to worryabout the weight of the stick at all. This is typical of these meter sticks thatare manufactured by the Red Herring Pedagogical Industries Group LLC ofEckveldt, South Dakota, and so often used in these Physics demonstrations.)-- At the "60cm" mark, 10cm from the pivot on the other side, is hanging aweight of 300N. That gives us 3,000 N-cm of moment working against the twoweights on the first side.-- In order to balance the whole thing, we have to provide only another(5,500 - 3,000) = 2,500 N-cm on the second side.-- All we can say is: The product of (the weight of a single weight hung fromthe second side) multiplied by (its distance in centimeters from the pivot) mustbe 2,500.-- The lightest weight that can do the job is 50N, if it's hung at the endofthe stick on the second side, 50cm from the pivot. If we have more weight toplay with, then it can be hung closer to the pivot, just as long as (weight) times (distance from the pivot) = 2,500 N-cm.
maby i am not sure because i am not paying 40$ just to watch wwe
A metre stick is usually marked in centimetres. So the distance is 4 cm = 40 mm.
39.4 inches but most people just say 40
20 000 dollars and if it is signed, 40 000 dollars