im afraid that's the fun of relationships. But when you meet the one person for you, you'll know it in your heart and he should know it in his
because... he is meant 2 b the most poplar.
Just study and you will know, or just ask someone in your family b/c not everyone will know and if no one in your family knows then ask us at (answers.com)
9a4-b2=36a-2b=2(18-b) But if you meant 9a^4-b^2 it is not possible to factor
one is at the pet shop , an other is at b cafe, an other is at b park .the other 2 i do not know
To find the measurement of one side of a triangle when you know the other two sides, you can use the Law of Cosines if you also know the included angle. The formula is ( c^2 = a^2 + b^2 - 2ab \cdot \cos(C) ), where ( c ) is the side opposite angle ( C ), and ( a ) and ( b ) are the other two sides. If the triangle is a right triangle, you can simply use the Pythagorean theorem: ( c^2 = a^2 + b^2 ).
let a=b => a^2=a*b subtract by b^2 on both sides => (a^2)-(b^2)=(a*b)-(b^2) (a+b)(a-b)=b(a-b) => a+b=b since a=b 2a=a => 2=1......
a^2 times b^2= c^2 a and b are the sides that connect in the 90° angle , c is the side you want to find. Know what I mean?
If a and b are rational, with a < b, then a + (b-a) [sqrt(2)/ 2] is an irrational number between a and b. This number is between a and b because sqrt(2)/2 is less than one and positive, so that a < a + (b-a) [sqrt(2)/3] < a + (b-a) [1] = b. To prove that a + (b-a) [sqrt(2)/2] is not rational, suppose that a + (b-a) [sqrt(2)/2] = p/q where p and q are integers. Then, sqrt(2) = ( p/q -a ) 2/(b-a) which is rational since the rationals are a field, closed under arithmetical operation, but sqrt(2) not rational (Look up the elementary proof if you do not know it.)
In a triangle with angles A, B,C and sides a, b, c with side a opposite angle A, side b opposite angle B, and side c opposite angle C: If you know 2 of the angles (b and c), the third (a) can be calculated as the sum of the angles must be 180°: a = 180° - (b + c) If you know 2 of the sides (b and c) and the angle between them (A), the third side (a) opposite the angle A can be calculated using the cosine rule: a^2 = b^2 + c^2 - 2 b c cos A If you know one side (a) and the angle opposite it (A), then if a side (b) is known, the angle opposite it (B) can be calculated, or if an angle (C) is known the side (c) opposite it can be calculated, using the sine rule: (sin A)/a = (sin B)/b = (sin C)/c = 1/(2R) where R is the radius of the circumcircle of the triangle.
a) Everyone knows what one and two are, so they will know 1 + 1 = 2 b) Assuming they do not know what one and two are, it will be impossible to explain to them 1 + 1 = 2, because these definitions are ESSENTIAL to prove 1 + 1 = 2.
Only one that I know of, you know that Strickland Banks one. I think Plan B might be bringing another one out soon.
i d know