Complete combustion is very hard to obtain, unless you have nearly perfect conditions and little cause for error.
Products that indicate incomplete combustion include carbon monoxide (CO) and soot or unburned carbon particles. This is because incomplete combustion results in insufficient oxygen supply for complete conversion of fuel into carbon dioxide and water.
If the combustion is complete, carbon dioxide and water.
The resulting products of the complete combustion are water and carbon dioxide.
Complete combustion of a hydrocarbon yields carbon dioxide & water; incomplete combustion yields carbon monoxide & water. By having excess oxygen you have enough oxygen to ensure complete combustion. For example the combustion of methane (CH4):complete combustion: CH4 + 2O2 --> CO2 + 2H2Oincomplete combustion: CH4 + 1.5O2 --> CO + 2H2OAs you can see you need a 1/2 mole less of oxygen for the incomplete combustion of methane. So as long as you have twice the amount (in terms of moles) of oxygen as methane you will ensure complete combustion. So anything in excess of that will also ensure complete combustion.
The main products of complete combustion are carbon dioxide (CO2) and water (H2O).
Complete combustion will result in the production of CO2 and H2O.
The general equation for the complete combustion of a hydrocarbon fuel such as fossil fuels is: hydrocarbon + oxygen → carbon dioxide + water For example, the complete combustion of methane (CH4) would be: CH4 + 2O2 → CO2 + 2H2O.
You think probable to molar heat, expressed in J/mol.
Combustion
energy is released and oxygen is consumed
Yes, more oxygen is used in incomplete combustion compared to complete combustion because incomplete combustion results in the partial burning of the fuel, leading to the formation of more byproducts like carbon monoxide and soot. This requires additional oxygen to combine with these byproducts, using up more oxygen overall.
The general chemical equation for the complete combustion of a hydrocarbon is: Hydrocarbon + O2 -> CO2 + H2O For example, the combustion of methane (CH4) can be represented as: CH4 + 2O2 -> CO2 + 2H2O