Math and Arithmetic
Algebra

# How can you use the 'completing the square' method to solve an equation when the coefficient of x squared is more than 1?

i want to solve few questions of completing square method can u give me some questions on it

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## Related Questions

Completing the square is a method to solve quadratic equations. To use this method you take the number without a variable and subtract it from both sides, so that it is on the opposite side of the equation. Then add the square of half the coefficient of the x-term to both sides. This will give you a perfect square equation to solve for.

Completing the square is one method for solving a quadratic equation. A quadratic equation can also be solved by several methods including factoring, graphing, using the square roots or the quadratic formula. Completing the square will always work when solving quadratic equations and is a good tool to have. Solving a quadratic equation by completing the square is used in a lot of word problems.I want you to follow the related link that explains the concept of completing the square clearly and gives some examples. that video is from brightstorm.

In mathematics, a quadratic equation is a polynomial equation of the second degree. The general form is Where x represents a variable, and a, b, and c, constants, with a &ne; 0. (If a = 0, the equation becomes a linear equation.) The constants a, b, and c, are called respectively, the quadratic coefficient, the linear coefficient and the constant term or free term. The term "quadratic" comes from quadratus, which is the Latin word for "square." Quadratic equations can be solved by factoring, completing the square, graphing, Newton's method, and using the quadratic formula (given below). One common use of quadratic equations is computing trajectories in projectile motion. Because it is in the form of ax^2+bx+c=0

Completing the square is a method used to solve a quadratic function. This is a handy method when there are two instances of the same variable in the function.

Completing the square is one method for solving a quadratic equation. A quadratic equation can also be solved by factoring, using the square roots or quadratic formula. Solving quadratic equations by completing the square will always work when solving quadratic equations-You can also use division or even simply take a GCF, set the quantities( ) equal to zero, and subtract or add to solve for the variable

Equation of the circle is: x2 + y2 = 12x - 10y - 12 which can written as: x2 - 12x + y2 + 10y = -12 Now by the method of completing square we can get the coordinates of the center of the circle: Coefficient of x2 = 1 Coefficient of x = -12 = -2(6) So -12x can be written as -2(x)(6) ...(1) It is clear that by adding suitable term we obtain (a - b)2 or (a + b)2 The term -2ab is in the expansion of (a - b)2 so: From 1 it is clear that b is 6. So we need to add 62 to both sides of the equation. Coefficient of y2 = 1 Coefficient of y = 10 = 2(5) So 10y can be written as 2(y)(5) ...(2) The term 2ab is in the expansion of (a + b)2 so: From 2 it is clear that b is 5. So we need to add 52 to both sides of the equation. The equation of circle, now, becomes: x2 - 12x + 62 + y2 + 10y + 52 = -12 + 62 + 52 (x - 6)2 + (y + 5)2 = 49 (x - 6)2 + (y + 5)2 = 72 (x - 6)2 + (y - (-5))2 = 72 So the coordinates of the center is 6,-5 and its radius is 7 units.

Using the quadratic equation formula is a method of solving quadratic equations.

The first step, in solving a quadratic equation in a variable x using this method, is to complete the square defined by the terms in x2 and x, by adding and subtracting a suitable constant.

You describe the resultant computed using the graphical method by connecting the vectors head to tail. The difference from the tail of the first one to the head of the last one is the resultant vector. To determine resultant vector with the component method you use the formula x(squared) + y(squared) = R (squared).

36.1. You take the coefficient of x : = 122. Halve it : = 63. Then square it : = 364. Add it.This gives x2 + 12x + 36 = (x + 6)2The above method only works if the coefficient of x2 is 1. If it is not then the processs is slightly more complicated.

You can solve a quadratic equation 4 different ways. graphing, which is quick but not reliable, factoring, completing the square and using the quadratic formula. There is a new fifth method, called Diagonal Sum Method, that can quickly and directly give the 2 roots in the form of 2 fractions, without having to factor the equation. It is fast, convenient, and is applicable whenever the equation can be factored. Finally, you can proceed solving in 2 steps any given quadratic equation in standard form. If a=1, solving the equation is much simpler. First, you always solve the equation in standard form by using the Diagonal Sum Method. If it fails to find answer, then you can positively conclude that the equation is not factorable, and consequently, the quadratic formula must be used. In the second step, solve the equation by using the quadratic formula.

His method to figure out the difficult algebra equation was sucessful.

I could not figure out the math equation. The new data did not fit the existing equation. An equation can be a math formula or standard method.

1 By factorizing it 2 By sketching it on the Cartesian plane 3 By finding the difference of two squares 4 By completing the square 5 By using the quadratic equation formula 6 By finding its discriminant to see if it has any solutions at all

in computational mtd,like chemoffice there r options like compute prop. where along with basic prop. partition coefficient can be calculated

The theory of gas diffusion coefficient of acetone using the winkelmann method is to diffuse the gas into a volatile liquid. This can be done by confining the liquid in a small narrow tube and observing the rate of evaporation.

There are 3 main ways to solving a quadratic equation of the from ax2+bx+c=0 The first, also the quickest and easiest, is factorising the equation into the form of (ax+b)(bx+c)=0 implying that either x=-a/b or x=-c/b, for this equation you would factorise into (x-7)(x+3)=0 The second is to use the formula x=(-b&plusmn;&radic;(b2-4ac))/2a and just put the relative numbers in from your equation. The final is the 'completing the square' method, where you separate the variable part into the form (x+b/2)2+c-(b/2)2=0 (here we are assuming a=1) leading to x=&plusmn;&radic;((b/2)2-c)-b/2. This may look more complicated that the formulae method but can sometimes be a lot quicker if you become used to this method and is sometimes needed when the second method leaves you with taking the squareroot of a negative number. For the equation x2 - 4x - 21=0, it is easiest to use the first or third method, either way you obtain x=7 or -3.

This is a quadratic equation, and so you it falls under the rule: ax squared + bx + c. This means you need to times the 2x squared by 5, which is 10. Then you need to find the factors of ten, i.e. 2 and 5, 10 and 1. You need to find the pair of factors that add to make 7x, which would be 2 and 5. you then need to put these into the equation - it would become 2x squared + 2x (as one equation) and 5x + 5 would be another equation. we can see that 2x squared and 2x have 2x in common, and so the answer for that would be 2x (x + 1). the second equation would be 5 (x + 1). the two equations have x + 1 in common, and that would make up the first set of brackets. you then add the rest (2x +5) and your answer would be (x+1) (2x+5). FOIL is a different method used for 'easier' equations - less complicated. :)

Completing the square is a technique used to find the zeros/solutions to a polynomial equation; ex) x2 + 2x = 15. To complete the square, one must have a trinomial square on one side of the equation. To do so, add 1 to each side of the previous equation. x2 + 2x + 1 = 16. This will allow you to factor the first side of the equation so that you can take the square root of both sides. (x + 1)(x+1) = 16 =&gt; (x + 1)2 = 16. Take the square root of both sides: x + 1 = &plusmn; 4. Thus x = -3, 5

"one quarter of a number increased by 5" is an expression. It is NOT an equation. There is, therefore, no method that can be used to determine what the number is.

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