I think its through esterification, so react with methanol, CH3OH. The H from your acid should be lost along with the OH in the alcohol as H2O
Acetic acid (CH3COOH) is acidic because it donates a proton (H+) in solution. The presence of this proton gives acetic acid acidic properties.
There is one titratable proton in acetic acid (CH3COOH). It is the proton on the carboxyl group that can be donated in an acid-base reaction during titration.
Malonic acid has pKa values of 2.83 (pK1) and 5.69 (pK2). If malonic esters are used then on treatment with a strong base like sodium ethoxide, the methylene (-CH2-) hydrogen can be deprotonated, but I am not sure if that is possible for malonic acid as that will lead to a tri-anion.
The two resonating structure of the anion formed after acetic acid gives up a proton are equivalent, and the negative charge rests on oxygen which is an electronegative element. But in case of phenoxide ion, the resonating structures are not equivalent, and negative charge rests on carbon which is an electropositive atom.
H2S and HS-
Acetic acid belongs to the C1 point group.
Because acetic acid have methyl group ,a electron donating group
Acetic acid belongs to the functional group of carboxylic acids.
The anion of acetic acid is called acetate ion. It is formed when acetic acid loses a proton (H+) and becomes negatively charged. The chemical formula for acetate ion is CH3COO-.
Iodoacetic acid is stronger than acetic acid because the presence of the electron-withdrawing iodine atom in iodoacetic acid stabilizes the conjugate base through inductive effects, making it more acidic compared to acetic acid. The iodine atom withdraws electron density from the carboxylic acid group, making it easier to donate a proton, resulting in a lower pKa value for iodoacetic acid.
Acetic acid is a stronger acid. Ethanol is an alcohol which is slightly acidic but usually neutral in nature.
Vinegar is dilute acetic acid, which is an acid.