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Volts time amps equals watts so watts divided by volts equal amps.
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Calculate the Power in watts dissipated by a resistor of 1000 ohms with 200 volts across it 2 watts 20 watts 40 watts 400 watts?
Ohms law states that V = I * R I = V/R R = V/I P = I*V Where V = Voltage, I=Current, R = Resistance and P = Power or Watt Watt is the amount of electricity flowing through a line which is (Voltage times Current in (Amperage) = Power or watts) To find the power dissipated by a resistor of 1000 ohms, we first find the current I. The voltage is given as 200volts. Therefore I = V/R = 200/1000 = 0.2Amps We said Power or Watt = I*V Therefore the Power or watts dissipated by a resistor of 1000 ohms will be P=I*V = 200*0.2 = 40 Watts
What will be the voltage drop across each what resistors A 160 Ohms B 100 Ohms C 82 Ohms D 120 Ohms.?
Ohm's Law requires you know two of three parameters to calculate the third. Volts = Amps x Ohms You need to know current flowing through resistance to calculate voltage drop.
How do you convert 2.2kVA to amps?
You can't convert kVA (kilovolt.amps) to current (amps) unless you know the source voltage and/or load resistance (ohms) which is drawing the current from the source. If you know the voltage in kilovolts, you just divide the kilovolt.amps figure by the number of kilovolts and the result is the current in amperes. If you know both source voltage and load resistance you can use Ohm's Law to get the current: I = V / R In words, Ohm's law is: Current (amps) = Voltage divided by Resistance (ohms)
If you have 500 watts at 4 ohms how many watts do you have at 8 ohms?
250 watts approximatelyI assume you have a constant voltage supply. According to P=V^2/R => P*R=V^2, you have a 44.7 volt supply. If you change Resistance to 8 ohms, P=44.7^2/8 => P=250 watts.
A circuit consists of two resistors of 5 ohms and 2 ohms connected in series if a current of 5 amps in the circuit the power dissipated in the 2 resisters will be?
Two resistors in series, one 5 ohms and one 2 ohms, with a current of 5 amperes, will have a power dissipation of 175 watts. Ohm's law: Voltage = current times resistance E1 = I R1 = (5) (5) = 25 volts E2 = I R2 = (5) (2) = 10 volts Power law: Power = current times voltage P1 = I E1 = (5) (25) = 125 watts P2 = I E2 = (5) (10) = 50 watts PT = P1 + P2 = 125 + 50 = 175 watts
What is the formula for electrical voltage?
Voltage(volts)=Power(watts)/Current (ampheres) Or Voltage=Curren X Resistance(Ohms) -X
What is the unit for the measure of voltage?
A) amperes B) volts C) watts D) ohms
How many watts of heat are being produced by the heating of 16 ohms and is connected to a voltage of 120 volts?
The power in watts is equal to the volts times the amps so that is 120 x 7.5.
Formula for watts and amps?
power in watts = voltage in volts x current in amps. or power in watts = current in amps x (resistance in ohms) squared i think what you meant was power in watts =(current in amps)squared x resistance in ohms
How are volts ohms and watts affected by each other?
For a fixed resistance (ohms) current increases as voltage increases. Since Watts equals Volts x Amps x Power Factor then Watts would increase as voltage increases. The resistance would usually be fixed, but if you had a variable load resistance as the resistance decreased and the voltage remained constant, the current would increase and watts would therefore increase. Watts = Volts x Amps x Power Factor Volts = Amps x Ohms Power Factor is 1 for a resistive load.
23V 470 ohms what is P?
23 volts across 470 ohms will dissipate about 1.1 watts. Power equals voltage squared divided by resistance.
1200 watts is equal to how many amps?
Use ohms law on any cal. divide watts into volts equal amps how many time does 120volts go into 1200watts=10amps <<>> 1200 watts is equal to zero amps. To determine the amperage associated with 1200 watts a voltage needs to be stated. I = W/E, Amps = Watts/Volts.
How many watts are in 30 ohms?
Without specific information I cannot answer your question, however you can work it out. For a dc or single phase system you need to know 2 simple laws. P=V x I & V=I x R where: P = power in watts V = Voltage in Volts I = Current in Amps R=Resistance in Ohms we can therefore derive that since I=V/R and P=V x I then P=V x V/R or vsquared over R or in your case R = V(squared) / P = 12 x 12 / 30 = 144/30 = 4.8 ohms Now use the formula supplied with your voltage value, and you will know what the resistance is . See isn't math fun.
4 ohms equals how many watts?
Ohms does not equal watts. You need to know what voltage is across the resistor to determine how many watts it is drawing or how many watts the resistor should be rated for.Power is the voltage across the resistor SQUARED divided by the resistance. If this 4 ohm resistor has 12 volts across it then the watts power is (12 x 12) / 4 = 36 watts.1 Watt equals 1 Volt times 1 Amp.
Calculate the Power in watts dissipated by a resistor of 1000 ohms with 200 volts across it 2 watts 20 watts 40 watts 400 watts?
Ohms law states that V = I * R I = V/R R = V/I P = I*V Where V = Voltage, I=Current, R = Resistance and P = Power or Watt Watt is the amount of electricity flowing through a line which is (Voltage times Current in (Amperage) = Power or watts) To find the power dissipated by a resistor of 1000 ohms, we first find the current I. The voltage is given as 200volts. Therefore I = V/R = 200/1000 = 0.2Amps We said Power or Watt = I*V Therefore the Power or watts dissipated by a resistor of 1000 ohms will be P=I*V = 200*0.2 = 40 Watts
How do you figure watts for 8 Ohm speakers?
The power rating of speakers has nothing specific to do with ohms. look at the Watts rating printed somewhere on the speakers
Can i use 10amp fuse for 1000 watts instant heater?
There are zero amps in 1000 watts. Watts are the product of amps x volts or I = W/E, watts divided by voltage. As you can see, that if no voltage is stated no amperage can be given. Once you find the voltage of the heater then use the following equation, Amps = Watts/Volts to find the current draw of the 1000 watt heater.
