All you have to do is convert the 6.5 g HCl solution into moles, and then plug that value into the molarity formula. If you need help, here are the formulas: # mol = (mass of substance)/(molar mass) - the molar mass is just the molecular mass of the substance expressed in grams :) Molarity (M) = (# mol solute)/(# L solution) - the solute, in this case, is the HCl, and the solution is just one, based on your question Happy Calculating!!!
yea it does, the solution or mixture turns cloudy.
yes, its called a salt water solution (saline)
Runoff I belive.
A solute is the substance that the solvent is being dissolved in. For some things (e.g. two liquids) it's a bit ambiguous. Typically if there's a need to specify which is which the predominant component is designated the solvent, though if water is one of the components then it is often considered to be the solvent even when it's not the primary ingredient. Rubbing alcohol, for example, is usually labeled as a 70% solution (of 2-propanol in water) and not as a 30% solution of water in 2-propanol.
Mechanical weathering.
Concentration of a solution is recorded in molarity (M). Molarity is the moles of solute divided my liters of solution. So to find the concentration of a solution, calculate the number of moles of the solute (the chemical being dissolved) and measure the number of liters of the solution (the water), then divide them.
The question, as worded, is a little ambiguous. Rather, the question you should be asking is “What is the molarity of a 125 ml aqueous solution containing 10.0g of acetone?” Acetone is roughly 58 grams per mole. Therefore, a 125 mil solution with 10 g of acetone would contain roughly 0.17 moles, and the molarity would be roughly 1.4See the Related Questions for more information about how to calculate the molarity of a solution
An example of a solution being a mixture would be muddy water or saltwater because they can be physically separated.
the molarity is found by: 19.52g/770mL x 1 mole/156.7g x 1000mL/1L=0.618 mole i got 156.7g by using the chemical makeup of the solution SnF2: Sn's atomic number being 118.7 and rounding F's atomic number to 19.
Crenation is an example of osmosis. In this process, the cell distorts and shrinks after being placed in a hypotonic solution.
There are no units of concentration. Concentration is written as density, which requires a mass measurement, and a volume measurement. The standard units for this is grams per liter.
As a thought experiment - suppose you mixed one liter of 1M HCl with 1 liter of 1M NaOH. The resulting solution (neglecting any density changes associated with mixing) would contain 2 liters with 1 mole of Cl- and 1 mole of Na+ with the balance being water (the H+ from the HCl and the OH- from the NaOH would just become part of the water). This would give you a 0.5 M solution of NaCl.
It measures the acidity or alkalinity of the solution, with 7 being neutral.It does this by referring to the negative lograrithm f the molarity of the H+ ion in the solution. This a pH of 2 (acidic) means there are 10-2 moles of H+ /liter in the liquid and a pH of 10 (basic) means there are 10-10moles of H+ /liter .
The answer depends on what you mean by "do". Does it mean calculate individually, calculate the probability of either one or the other (or both), calculate the probability of both, calculate some function of both (for example the sum of two dice being rolled)?
A solute is the substance being dissolved (example, sugar). The solvent is the liquid into which is it dissolved (example, coffee)A solute is present in a smaller amount and a solvent is present in a greater amount in a solution.
Molarity (M) = moles of solute (mol) / liter of solution (L)M = mol / LYou have 250 mL of Solution, which is250 mL x ( 1 L / 1000 mL ) = ( 250 / 1000 ) L = .25 LSolute is just what's dissolvedSolvent is just what it's being dissolved inSolution is the solute and the solvent.M = mol / LM = 0.65 mol / 0.25 Liters = 2.6 mol/LThe two numbers that you are given, 0.65 moles and 250 mL both have two significant figures, and the answer is two significant figures (2.6 mol/L)Therefore the answer is 2.6 mol/L.
Iodine solution is an efficient indicator for starch. It will go from a light brown colour to a black colour if starch is present and will stay light brown if no starch is present. Hope this Helps!