It is a simple AB + CD = AD + CB reaction so we would have:
NaOH + KCl -> NaCl + KOH
LiOH + KCl-->LiCl + KOH
This is an example of a double-replacement reaction.
They would undergo neutralization and give lithium bromide and water as products.
2KOH + BaCl2 --> Ba(OH)2 + 2KCl
The balanced equation is: KHCO3 + HCl -> KCl + CO2 + H2O The products of the reaction are potassium chloride, carbon dioxide and water.
Balanced:2 KOH + SO3 ----> K2SO4 + H2O
The compound copper (III) chloride doesn't exist !
2KClO3 --> 2KCl + 3O2
HCl + KOH ==> KCl + H2O
The balanced equation for copper(II) oxide and potassium chloride is CuO + 2KCl → CuCl2 + K2O When copper(II) oxide reacts with potassium chloride then it forms copper(II) chloride and potassium oxide.
KCl will not decompose
2K + Cl2 ---> 2KCl
The balanced equation is: KHCO3 + HCl -> KCl + CO2 + H2O The products of the reaction are potassium chloride, carbon dioxide and water.
2K+Cl2------->2KCl
4KClO3= 3KClO4+KCl
Balanced:2 KOH + SO3 ----> K2SO4 + H2O
It is impossible to balance that equation.
The compound copper (III) chloride doesn't exist !
2KClO3 --> 2KCl + 3O2
The equation is:2 KOH + H2SO4 = K2SO4 + 2 H2O
Ca+2 (aq) + C2O4-2 (aq) + H2O (l) --> CaC2O4 *H2O (s)