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How do you Differentiate and Integrate y equals 3 to the power of x?
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Answered 2009-12-08 14:25:15
dy/dx = 3^x * ln(3)
integral = (3^x) / ln(3)
To obtain the above integral...
Let y = 3^x
ln y = x ln 3
y = e^(x ln 3)
(i.e. 3^x is the same as e^(x ln 3) ).
The integral will then be 3^x / ln 3 (from linear composite rule and substitution after integration).
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