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Answered 2009-12-08 14:25:15

dy/dx = 3^x * ln(3)

integral = (3^x) / ln(3)

To obtain the above integral...

Let y = 3^x
ln y = x ln 3
y = e^(x ln 3)

(i.e. 3^x is the same as e^(x ln 3) ).

The integral will then be 3^x / ln 3 (from linear composite rule and substitution after integration).

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