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Top Answer

dy/dx = 3^x * ln(3)

integral = (3^x) / ln(3)

To obtain the above integral...

Let y = 3^x

ln y = x ln 3

y = e^(x ln 3)

(i.e. 3^x is the same as e^(x ln 3) ).

The integral will then be 3^x / ln 3 (from linear composite rule and substitution after integration).

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0dy/dx = 3 integral = (3x^2)/2

I can't integrate a-x /x-3 ?

integrate(x5x dx) simplifies to integrate(5x^2 dx), and using the power rule of integration, add one to the power of x and divide the term by that number. Thus, x5x dx integrated is (5/3)x^3

If m equals 3 then m to the 6th power (m6) equals 36 or 3 x 3 x 3 or 27

a, a^3*a^-2 is a^3+-2 which equals just a

8 to the power (2/3) equals 4.

3 to the 7th power times 3 to the 3rd power equals 59,049

10 to the power 3 = 1000

2 to the power of 3 equals 8.

3 to the 3rd power + 3 to the 3rd power = 54

3 to the ninth power equals 19,683 while 9 to the fourth power equals 6,561 (if i'm not mistaken) so.. 9 to the fourth power (<) 3 to the ninth power

8 to the power of 3 is... 8 times 8 which equals 64, but then you do 64 times 8 which equals 512 and that's 8 to the power of 3

3 to the negative sixth power equals 0.00137174211

8^3 = 512

It is: 19^3 = 6859

8 ^ 3 = 512.

log 3 is a constant, so d/dx log3, like d/dx of any constant, equals zero.

Three to the 4th power divided by 3 to the 7th power equals 0.03703703703

It can be as for example 9 to the power of 0.5 equals 3

2 to the power of -3 equals 0.125

3 to the power of 3 is the same as 3 cubed. To put it in an equation that would be 3x3x3 which equals 27.

If x has the power 2 then you want the integral of x2, I think. When you integrate this you get : x3/3 , plus a constant.

Reflexivity is a property of equality, i.e., X = X is always true. Thus -7 raised to the power of 3 equals -7 raised to the power of 3 is true.

3-7 equals 0.00045724737

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