Assuming the equation described is: w = (Cr)-2...
Remember that any value to a negative power can also be represented like this:
(Cr)-2 = 1/(Cr)2
Also note that we can distribute the power over multiplication. (This doesn't apply to addition!)
(Cr)2 = C2r2
So if we rewrite the equation with this, we get
w = 1/(C2r2)
If we invert both sides and then divide by C2 on both sides, we get
1/w = C2r2 → 1/(wC2) = r2
Take the square root of both sides, and you'll have the equation in terms of r:
r = sqrt[1/(wC2)]
The biggest step was realizing that anything to a negative power can be inverted to find the same with a positive power. For example, 2-2, if you type it in your calculator, gives you 0.25, or 1/4. If we do what we did above, we can take 2-2 and make it 1/(22), which also equals 1/4. This applies to any negative power, and is a powerful technique for solving equations with negative exponents.
y = 2 (Divide each side of the equation by -45)
Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".
b = 14
No. There is not enough information in the equation x + 2y = 2, by itself, to solve it. There are an infinite number of solutions. A second equation, or information to allow a second equation to be derived, must be given to find a solution.
Set up the equation and solve: x + 5 = -13 (next subtract 5 from each side of the equation to solve for x) x = -18
x=2 because 9-(14)=-5
Better formatting is cos(2x+20)=-0.5
This equation is unsolvable since there are two unknowns and only one equation. You would require a second equation in order to solve it.
It is not an equation if it does not have an equals sign. You could simplify it but not solve it.
a equals 5
You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".
yes