Reference:cprogramming-bd.com/c_page2.aspx# reverse number
In python, type the following into a document. NOTE: Sentences following a # symbol are comments, and are not necessary for the program to run. #!/usr/bin/python #This program takes a input from a user and reverses it. number = input("Type a number: ") #This takes input from a user. a = len(number) #This finds the length of the number reverse = "" #This sets the variable reverse to an empty string. for i in number: a = a-1 #The places in a string start from 0. The last value will be the length minus 1.reverse = reverse + number[a] #Makes the number's last digit the new string's first. print("The reverse of", number, "is", reverse + ".") #prints the resulting string. This program will take any sequence of characters and reverse them. The final value is a string, but if an integer is needed, one needs only to add the line reverse = int(reverse) above the print statement. However, this will stop the program from being able to reverse strings, as it is not possible to convert a string to an integer if it is not a number.
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Write a function that implements an algorithm that checks to see if a particular integer is prime (returning a boolean). Write a program that uses that function on each number from 1 to 100, and if true, displays that number.
The number 5789 is already an integer.
write the javascript code to display the reverse no. of given no. (e.g. 247 reverse of 742)
prompt x floor(x + .5) -> x disp x
Yes. An integer has no fractions and if you can write it, it's a real number!
int isDivisibleByTwo(int N) return N % 2 == 0;
187 is already an integer because it is a whole number
500% as an integer or whole number is 5
2,000,000 an integer is any whole number
To check if a number is a palindrome, reverse the number and see if it is equal to the original number. If so, the number is a palindrome, otherwise it is not. To reverse a number, use the following function: int reverse(int num, int base=10) { int reverse=0; while( num ) { reverse*=base; reverse+=num%base; num/=base; } return(reverse); }