Reference:cprogramming-bd.com/c_page2.aspx# reverse number
In python, type the following into a document. NOTE: Sentences following a # symbol are comments, and are not necessary for the program to run. #!/usr/bin/python #This program takes a input from a user and reverses it. number = input("Type a number: ") #This takes input from a user. a = len(number) #This finds the length of the number reverse = "" #This sets the variable reverse to an empty string. for i in number: a = a-1 #The places in a string start from 0. The last value will be the length minus 1.reverse = reverse + number[a] #Makes the number's last digit the new string's first. print("The reverse of", number, "is", reverse + ".") #prints the resulting string. This program will take any sequence of characters and reverse them. The final value is a string, but if an integer is needed, one needs only to add the line reverse = int(reverse) above the print statement. However, this will stop the program from being able to reverse strings, as it is not possible to convert a string to an integer if it is not a number.
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Write a function that implements an algorithm that checks to see if a particular integer is prime (returning a boolean). Write a program that uses that function on each number from 1 to 100, and if true, displays that number.
The number 5789 is already an integer.
prompt x floor(x + .5) -> x disp x
write the javascript code to display the reverse no. of given no. (e.g. 247 reverse of 742)
Yes. An integer has no fractions and if you can write it, it's a real number!
int isDivisibleByTwo(int N) return N % 2 == 0;
2,000,000 an integer is any whole number
187 is already an integer because it is a whole number
500% as an integer or whole number is 5
To check if a number is a palindrome, reverse the number and see if it is equal to the original number. If so, the number is a palindrome, otherwise it is not. To reverse a number, use the following function: int reverse(int num, int base=10) { int reverse=0; while( num ) { reverse*=base; reverse+=num%base; num/=base; } return(reverse); }