int x = 1, y = 2, z = 3;
int f = x + y + z;
it is simple arithmetic. to solve, just add the numbers using the addition property and recieve the answer of 34
Just add the numbers, and divide the result by 3 (since there are 3 numbers).
41 plus 3 equals 44. You add the two numbers together to get the answer.
7 7/12 plus 3 8/9
Standard numbers refer to the numerical values used in basic arithmetic. In the case of "60 plus 3," the standard numbers are 60 and 3. When you add them together, the result is 63.
If you add all the numbers from 1 to 98, the total is 4851.
First add all the negative numbers. It -4+-3+-8 is -15. Now 3+9=12So we need to as 12 to -15 which is the same as 12-15 or -3.When you add negative numbers you can just add them like positives then place the negative sign in front of you answer. Adding a positive and a negative is like subtracting the negative one from the positive one. That is what I did.
To add 3 and 14 plus 2 and 25, first add the whole numbers and the fractions separately. The whole numbers are 3 + 2 = 5, and the fractions are 14 + 25 = 39. Therefore, the final result is 5 and 39.
There are no two real numbers that do. Using complex numbers, these two do: (-3/2 + i√151/2) & (-3/2 - i√151/2) Two numbers that add to -3 and multiply to -40 are -8 & 5 Two numbers that add to 3 and multiply to -40 are 8 & -5 Two complex numbers that add to 3 and multiply to 40 are (3/2 + i√151/2) & (3/2 - i√151/2)
Oh, dude, adding mixed numbers with like denominators is a piece of cake! Just add the whole numbers together, then add the fractions together. It's like putting together a puzzle, but with numbers. So, if you have 2 and 1/4 plus 3 and 1/4, you just add 2 plus 3 to get 5, and 1/4 plus 1/4 is 2/4, which simplifies to 1/2. Boom, you got 5 and 1/2! Easy peasy.
3
It cannot be done using real numbers. However, it can be done using complex numbers: 16y² + 4y + 1 = ¼(8y + (1 + i√3))(8y + (1 - i√3))