Balanced equation:
12 HClO4 + P4O10 = 4 H3PO4 + 6 Cl2O7
The answer is 699 moles perchloric acid.
P4 3o2 ---> 2po5
P4O10 + 6H2O = 4H3PO4 Phosphorus oxide reacst with water to produce phosphoric acid.
Look at the products. You should already know that one is bound to be water, H2O. You know that the OH comes from KOH, and the H comes from H3PO4. So ask yourself the question: How many OH and how many H are available? You can see that since you have three of one, you will also need three of the other, so you need 3 of the KOH, right? So this is the equation: 3KOH + H3PO4 -> 3H2O + K3PO4
Dissolve into water and it actually reacts with the water to form H3PO4, phosphoric acid.
This equation is P4O10 + 6 H2O -> 4 H3PO4.
4p+5o2->p4o10
4p+5o2->p4o10
A bit vague, but various compounds are H3PO4 - phosphoric acid P4O10 - Phosphorus oxide PO43- - Any element with the phosphate group
71/284 = x / 4 x = 1 mole
There are two reaction equations for phosphate ion and water. They two equations are: i) HPO4 2- + H2O => H3O+ + PO4 3- ii) HPO4 2- + H2O => OH- + H2PO4 -
__Pb(OH)2 + (2)HCL----> (2)H2O + __PbCl2 Pb=1---->Pb=1 O=2----->O=2 H=4----->H=4 Cl=2---->Cl=2 all elements match on both sides