P4 3o2 ---> 2po5
P4O10 + 6H2O = 4H3PO4 Phosphorus oxide reacst with water to produce phosphoric acid.
The chemical equation for the reaction of phosphorus with oxygen to form phosphorus pentoxide is: 4 P + 5 O2 → P4O10.
Look at the products. You should already know that one is bound to be water, H2O. You know that the OH comes from KOH, and the H comes from H3PO4. So ask yourself the question: How many OH and how many H are available? You can see that since you have three of one, you will also need three of the other, so you need 3 of the KOH, right? So this is the equation: 3KOH + H3PO4 -> 3H2O + K3PO4
PH3 + O2 ----> P4O10 + H2O 4PH3 + 8O2 ----> 1P4O10 + 6H2O P4H3O10 = P4H3O10 Balanced Answer : 4,8,1,6
In this reaction H3O+ is the conjugate acid. The original acid in this reaction is H3PO4
Balanced equation:12 HClO4 + P4O10 = 4 H3PO4 + 6 Cl2O7
P4O10 + 6H2O = 4H3PO4 Phosphorus oxide reacst with water to produce phosphoric acid.
The balance is 2N2 +2O2= 4NO
liho+h2s=
cl2o7+h2o
C3h8 + 5o2 -> 3co2 + 4h2o
4Li + O2 -> 2Li2O
2Al+3S--->Al2S3
The chemical equation for the reaction of phosphorus with oxygen to form phosphorus pentoxide is: 4 P + 5 O2 → P4O10.
P + Na(OH) + H20 = NaH2PO2 + PH3
2 PbO + C -> 2 Pb + CO2
3H2C2O4 + 2K2MnO4 = 6CO2 + 2K2O + Mn2O3 + 3H2O