Zn + CuSO4 --> ZnSO4 + Cu
double replacement
Zn + CuSO4 -> ZnSO4 + Cu
copper (II) sulfate is CuSO4 ; Zinc sulfate is ZnSO4 Zn + CuSO4 --> ZnSO4 + Cu
It is a single displacement reaction. No balancing is needed in the resulting equation. Zn + CuBr2 ----> ZnBr2 + Cu
Cl H Zn -apex Fojus xD
May be. Thermodynamics info is needed too.
Cu is being reduced and Zn is being oxidized, hence Zn + CuSO4 --> ZnSO4 + Cu
The net ionic equation is Zn + 2H+ --> Zn2+ + H2
The balanced equation is as follows: Zn(s) + 2HCl(aq) --> ZnCl2(aq) + H2(g)
Zn + CuSO4 --> ZnSO4 + Cu 1.75g CuSO4 * (1moleCuSO4/159.62gCuSO4) * (1moleZn/1moleCuSO4) * (65.38gZn/1moleZn) = .7168g Zn 2.00g Zn - .7168g Zn = 1.2832g Zn in Excess
Zn+ H2O ---> ZnO + H2 Zn+ H2O ---> ZnO + H2
Zn + CuSO4 -> ZnSO4 + Cu (molecular equation) Zn (s) + SO4 2+ + Cu 2+ --> Cu (s) + Zn 2+ + SO4 2+ (ionic equation) Cu + Zn(s) ---> Cu (s) + Zn (net ionic)