Cs2 + 3o2 ------->>> co2 + 2so2
Both CO2 and CS2 are held by Van der Waals' forces but CO2 has a smaller number of electrons than CS2.This leads to weaker forces between the molecules .Therefore, CO2 is a gas while CS2 is a liquid.
CS2 has a higher molar mass than CO2
As it is an alkali metal, it forms the Cs+ ion
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Cs2 + 3o2 --> co2 + 2so2
The equation is CS2 + 3 O2 -> CO2 + 2 SO2.
...+13o2
This chemical reaction is:CS2 + 3 Cl2 = CCl4 + S2Cl2
To determine how much excess reactant remains, we need to calculate the amount of O2 needed to react completely with CS2. Since the ratio of CS2 to O2 is 1:3, one mole of CS2 will react with three moles of O2. If there is an excess of O2 given, you would need to compare the actual amount of O2 present to the amount required for complete reaction with CS2 to find the excess.
Both CO2 and CS2 are held by Van der Waals' forces but CO2 has a smaller number of electrons than CS2.This leads to weaker forces between the molecules .Therefore, CO2 is a gas while CS2 is a liquid.
The chemical equation CS2 + 2 Cl2 -> CCl4 + S2Cl2 is not balanced, because it shows four chlorine atoms on the left but six chlorine atoms on the right. The corresponding balanced equation is CS2 + 3 Cl2 -> CCl4 + S2Cl2.
CS2 has a higher molar mass than CO2
Cs2 + 3 o2 → co2 + 2 so2
The chemical formula for carbon disulfide is CS2. It consists of one carbon atom bonded to two sulfur atoms.
The strength of intermolecular forces increases from CO2 (dispersion forces only) to CS2 (dispersion and dipole-dipole forces) to CSe2 (dispersion, dipole-dipole, and hydrogen bonding forces). This progression reflects the increasing polarity and molecular weight of the molecules, resulting in stronger intermolecular attractions.
Carbon dioxide and sulfur dioxide are formed when carbon disulfide vapor is burned in excess oxygen.
As it is an alkali metal, it forms the Cs+ ion