2Fe+3Cl2------>2FeCl3
Cl + O3 ----------- ClO + O2 ClO + O ----------- Cl + O2 First of all the fisrt reaction is all ready balanced 1 Cl and 3 O ----Cl0 ( 1 Cl and 1 O) + O2. But for the general ecuation or global ecuation is O3 + O ------(CL)----- 2O2. Where the cl acts as a catalyst.
2Al + 3Cl2 --> 2AlCl3
This didn't answer the question. The question asked "How do you balance...." so it is likely that the person who posted will have to show their work and needs to see how to do it for the future.
The balanced equation would be:
2Al + 3Cl2 -> 2AlCL3
The balanced equation is Cl2 + 2NaI --> I2 + 2NaCl
2Al+3Cl2-->2AlCl3
3F2 + 2AlCl3 ----> 2AlF3 + 3Cl2
3 Cl2 + 2AlBr3 = 2 AlCl3 + 3 Br2
no. Na+Cl--> NaCl
2 Na + Cl2 = 2 NaCl
The chemical equation is:2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2
The chemical equation is:2 Al +3 CuCl2 = 3 Cu + 2 AlCl3
A balanced equation for the decomposition of sodium chlorate to produce sodium chloride and elemental oxygen is 2 NaClO3 -> 2 NaCl + 3 O2.
Given the balanced equation2Al + 6HBr --> 2AlBr3 + 3H2In order to find how many grams of HBr are required to produce 150g AlBr3, we must convert from mass to mass (mass --> mass conversion).150g AlBr3 * 1 mol AlBr3 * 6 molecules HBr = 136.52 or 137g HBr----------- 266.6g AlBr3 * 2 molecules AlBr3
MgCl2
The chemical equation is:2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2
The chemical equation is:2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2
The chemical equation is:2 Al +3 CuCl2 = 3 Cu + 2 AlCl3
This chemical reaction is:2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2
The balanced equation is Al(OH)3 + 3HCl ==> 3H2O + AlCl3
The balanced equation looks like this: k2so4+alcl3 kcl+al2(5o4)3
The chemical equation is:Al2(CO3)3 + 3 ZnCl2 = 2 AlCl3 + 3 ZnCO3
This equation is Al2O3 + 6 HCl = 2 AlCl3 + 3 H2O.
A balanced equation for the decomposition of sodium chlorate to produce sodium chloride and elemental oxygen is 2 NaClO3 -> 2 NaCl + 3 O2.
3Ag2SO4 + 2AlCl3 -> 6AgCl + Al2(SO4)3
3
The chemical reaction isȘAlI3 + 3 Br2 = 2 AlBr3 + 3 I2