The balanced chemical equation for this reaction is:
2KBr + Al(NO3)3 → 2KNO3 + AlBr3
The balanced equation for the reaction between potassium bromide and aluminum nitrate is 6KBr + Al(NO3)3 → 2AlBr3 + 3KNO3.
The word equation for potassium bromide and iodine water is: potassium bromide + iodine water -> potassium iodide + bromine.
The bromide ion has a charge of -1. In the ionic compound potassium bromide (KBr), potassium has a charge of +1 to balance the -1 charge of the bromide ion.
The bromide ion (Br-) has a charge of -1. In the formation of potassium bromide (KBr), the potassium ion (K+) has a charge of +1, and the bromide ion has a charge of -1 to balance the overall charge of the compound.
The balanced equation for potassium bromide (KBr) and ammonium chloride (NH4Cl) is: KBr + NH4Cl → KCl + NH4Br
The balanced equation for the reaction between potassium bromide and aluminum nitrate is 6KBr + Al(NO3)3 → 2AlBr3 + 3KNO3.
The word equation for potassium bromide and iodine water is: potassium bromide + iodine water -> potassium iodide + bromine.
The bromide ion has a charge of -1. In the ionic compound potassium bromide (KBr), potassium has a charge of +1 to balance the -1 charge of the bromide ion.
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
The bromide ion (Br-) has a charge of -1. In the formation of potassium bromide (KBr), the potassium ion (K+) has a charge of +1, and the bromide ion has a charge of -1 to balance the overall charge of the compound.
Three ions of bromide will combine with one ion of aluminum to form aluminum bromide (AlBr3). This is because aluminum has a +3 charge and bromide ions each have a -1 charge, so three bromide ions are needed to balance the +3 charge of aluminum.
The balanced equation for potassium bromide (KBr) and ammonium chloride (NH4Cl) is: KBr + NH4Cl → KCl + NH4Br
The balanced chemical equation for potassium bromide is KBr(s) --> K+(aq) + Br-(aq).
chlorine plus potassium bromide gives bromine plus potassium chloride. Here is the symbol equation, but remember that the numbers AFTER the symbols should be subscripts. Cl2 + 2KBr = Br2 + 2KCl
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
2 KBr + BaI2 ----> 2 KI + BaBr2
KBr + H2O = Kaq+ Braq- Haq+ OHaq-