The balanced chemical equation for this reaction is:
2KBr + Al(NO3)3 → 2KNO3 + AlBr3
The balanced equation for the reaction between potassium bromide and aluminum nitrate is 6KBr + Al(NO3)3 → 2AlBr3 + 3KNO3.
The word equation for potassium bromide and iodine water is: potassium bromide + iodine water -> potassium iodide + bromine.
The bromide ion has a charge of -1. In the ionic compound potassium bromide (KBr), potassium has a charge of +1 to balance the -1 charge of the bromide ion.
The bromide ion (Br-) has a charge of -1. In the formation of potassium bromide (KBr), the potassium ion (K+) has a charge of +1, and the bromide ion has a charge of -1 to balance the overall charge of the compound.
The balanced equation for potassium bromide (KBr) and ammonium chloride (NH4Cl) is: KBr + NH4Cl → KCl + NH4Br
The balanced equation for the reaction between potassium bromide and aluminum nitrate is 6KBr + Al(NO3)3 → 2AlBr3 + 3KNO3.
The word equation for potassium bromide and iodine water is: potassium bromide + iodine water -> potassium iodide + bromine.
The bromide ion has a charge of -1. In the ionic compound potassium bromide (KBr), potassium has a charge of +1 to balance the -1 charge of the bromide ion.
The bromide ion (Br-) has a charge of -1. In the formation of potassium bromide (KBr), the potassium ion (K+) has a charge of +1, and the bromide ion has a charge of -1 to balance the overall charge of the compound.
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
Three ions of bromide will combine with one ion of aluminum to form aluminum bromide (AlBr3). This is because aluminum has a +3 charge and bromide ions each have a -1 charge, so three bromide ions are needed to balance the +3 charge of aluminum.
The balanced equation for potassium bromide (KBr) and ammonium chloride (NH4Cl) is: KBr + NH4Cl → KCl + NH4Br
The balanced chemical equation for potassium bromide is KBr(s) --> K+(aq) + Br-(aq).
chlorine plus potassium bromide gives bromine plus potassium chloride. Here is the symbol equation, but remember that the numbers AFTER the symbols should be subscripts. Cl2 + 2KBr = Br2 + 2KCl
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
2 KBr + BaI2 ----> 2 KI + BaBr2
KBr + H2O = Kaq+ Braq- Haq+ OHaq-