Bromine and Potassium iodide react to form Potassium bromide and Iodine.
Br2 + (2e)- --> 2 Br- 2I- --> I2 + (2e)-
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
The reaction between potassium iodide and bromine produces potassium bromide and iodine. This is a redox reaction where bromine gets reduced to bromide ions, while iodide ions get oxidized to form elemental iodine. The balanced chemical equation for this reaction is 2 KI + Br2 → 2 KBr + I2.
well i don't really know the word chemical equation, but the balanced form is:2KI(aq) + Br(aq) --> I2(s) + 2KBr(aq)so if you just figure out the word form of the elements in the equation you'll figure it out..
Yes, liquid bromine can react with potassium iodide to form potassium bromide and elemental iodine. This reaction is a displacement reaction, where the more reactive element (bromine) displaces the less reactive element (iodine).
Br2 + (2e)- --> 2 Br- 2I- --> I2 + (2e)-
potassium
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
The reaction between potassium iodide and bromine produces potassium bromide and iodine. This is a redox reaction where bromine gets reduced to bromide ions, while iodide ions get oxidized to form elemental iodine. The balanced chemical equation for this reaction is 2 KI + Br2 → 2 KBr + I2.
well i don't really know the word chemical equation, but the balanced form is:2KI(aq) + Br(aq) --> I2(s) + 2KBr(aq)so if you just figure out the word form of the elements in the equation you'll figure it out..
Yes, liquid bromine can react with potassium iodide to form potassium bromide and elemental iodine. This reaction is a displacement reaction, where the more reactive element (bromine) displaces the less reactive element (iodine).
The word equation for the reaction between potassium and iodine is: potassium + iodine → potassium iodide.
In a reaction between bromine and potassium iodide, bromine acts as an oxidizing agent, not a reducing agent. It oxidizes iodide ions to form iodine molecules while itself being reduced to bromide ions.
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
Please mention this reaction.
When potassium iodide is added to a solution of bromine, a reaction occurs forming potassium bromide and iodine. The iodine produced in the reaction is responsible for the color change in the solution from orange to brown/black.
The reaction between bromine and aqueous strontium iodide is a double displacement reaction. Bromine replaces iodide in strontium iodide, forming strontium bromide and iodine. The balanced chemical equation is: Br2 + SrI2 --> SrBr2 + I2.