Its actually:
2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
The reaction between potassium iodide and bromine produces potassium bromide and iodine. This is a redox reaction where bromine gets reduced to bromide ions, while iodide ions get oxidized to form elemental iodine. The balanced chemical equation for this reaction is 2 KI + Br2 → 2 KBr + I2.
Yes, liquid bromine can react with potassium iodide to form potassium bromide and elemental iodine. This reaction is a displacement reaction, where the more reactive element (bromine) displaces the less reactive element (iodine).
Br2 + (2e)- --> 2 Br- 2I- --> I2 + (2e)-
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
The word equation for potassium bromide and iodine water is: potassium bromide + iodine water -> potassium iodide + bromine.
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
The reaction between potassium iodide and bromine produces potassium bromide and iodine. This is a redox reaction where bromine gets reduced to bromide ions, while iodide ions get oxidized to form elemental iodine. The balanced chemical equation for this reaction is 2 KI + Br2 → 2 KBr + I2.
2 KBr + BaI2 ----> 2 KI + BaBr2
No. However, bromine would displace iodine in potassium iodide.
Yes, liquid bromine can react with potassium iodide to form potassium bromide and elemental iodine. This reaction is a displacement reaction, where the more reactive element (bromine) displaces the less reactive element (iodine).
In a reaction between bromine and potassium iodide, bromine acts as an oxidizing agent, not a reducing agent. It oxidizes iodide ions to form iodine molecules while itself being reduced to bromide ions.
Br2 + (2e)- --> 2 Br- 2I- --> I2 + (2e)-
This is a double displacement reaction where bromine (Br2) reacts with potassium iodide (KI) to form potassium bromide (KBr) and iodine (I2) by exchanging ions. The bromine displaces the iodine from potassium iodide to form potassium bromide and free iodine.
The reaction between bromine water and potassium iodide forms potassium bromide and iodine. This is a redox reaction where bromine is reduced to bromide ions and iodide ions are oxidized to form iodine. The solution will change color from orange/brown to colorless as the iodine precipitates out.
well i don't really know the word chemical equation, but the balanced form is:2KI(aq) + Br(aq) --> I2(s) + 2KBr(aq)so if you just figure out the word form of the elements in the equation you'll figure it out..