Br2 + (2e)- --> 2 Br-
2I- --> I2 + (2e)-
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
The reaction between potassium iodide and bromine produces potassium bromide and iodine. This is a redox reaction where bromine gets reduced to bromide ions, while iodide ions get oxidized to form elemental iodine. The balanced chemical equation for this reaction is 2 KI + Br2 → 2 KBr + I2.
The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
potassium
Its actually: 2KI(aq)+Br2(aq)-> I2(s)+2KBr(aq)
Br2 (g) + 2 KI (aq) 2KBr (aq) + I2 (s)
The reaction between potassium iodide and bromine produces potassium bromide and iodine. This is a redox reaction where bromine gets reduced to bromide ions, while iodide ions get oxidized to form elemental iodine. The balanced chemical equation for this reaction is 2 KI + Br2 → 2 KBr + I2.
The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
The balanced symbol equation between chlorine and potassium iodide is: Cl2 + 2KI -> 2KCl + I2
well i don't really know the word chemical equation, but the balanced form is:2KI(aq) + Br(aq) --> I2(s) + 2KBr(aq)so if you just figure out the word form of the elements in the equation you'll figure it out..
The word equation for potassium bromide and iodine water is: potassium bromide + iodine water -> potassium iodide + bromine.
The balanced chemical equation for the reaction between barium acetate and potassium iodide is: Ba(CH3COO)2 + 2KI -> BaI2 + 2KCH3COO
The reaction between bromine and aqueous strontium iodide is a double displacement reaction. Bromine replaces iodide in strontium iodide, forming strontium bromide and iodine. The balanced chemical equation is: Br2 + SrI2 --> SrBr2 + I2.
The balanced equation is 2 KI + Pb(NO3)2 -> 2 KNO3 + PbI2.