A reaction doesn't occur.
The reaction between potassium phosphate (K3PO4) and barium acetate (Ba(C2H3O2)2) will produce barium phosphate (Ba3(PO4)2) and potassium acetate (KCH3COO). The balanced chemical equation for this reaction is 3K3PO4 + Ba(C2H3O2)2 -> Ba3(PO4)2 + 6KCH3COO.
The balanced chemical equation for barium chloride (BaCl2) reacting with potassium sulfate (K2SO4) is: BaCl2 + K2SO4 -> BaSO4 + 2KCl. This reaction forms barium sulfate (BaSO4) and potassium chloride (KCl).
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
The net ionic equation for sodium acetate (NaC2H3O2) and barium sulfide (BaS) is: Ba2+(aq) + 2CH3COO-(aq) -> Ba(CH3COO)2(s) This equation shows the formation of insoluble barium acetate precipitate.
The balanced equation is: K2CO3(aq) + BaCl2(aq) -> 2KCl(aq) + BaCO3(s).
The reaction between potassium phosphate (K3PO4) and barium acetate (Ba(C2H3O2)2) will produce barium phosphate (Ba3(PO4)2) and potassium acetate (KCH3COO). The balanced chemical equation for this reaction is 3K3PO4 + Ba(C2H3O2)2 -> Ba3(PO4)2 + 6KCH3COO.
When potassium metal (K) is added to a solution of barium acetate (Ba(C₂H₃O₂)₂), a single displacement reaction occurs. The balanced formula equation for this reaction is: [ 2 \text{K} + \text{Ba(C}_2\text{H}_3\text{O}_2\text{)}_2 \rightarrow \text{Ba} + 2 \text{KC}_2\text{H}_3\text{O}_2. ] In this reaction, potassium displaces barium, forming barium metal and potassium acetate.
The balanced chemical equation for barium chloride (BaCl2) reacting with potassium sulfate (K2SO4) is: BaCl2 + K2SO4 -> BaSO4 + 2KCl. This reaction forms barium sulfate (BaSO4) and potassium chloride (KCl).
The BaSO4 (barium sulfate) will precipitate out of solution because it is insoluble, whereas the KCl2 is soluble and will remain dissolved. The balanced equation is: K2SO4 + BaCl2 -----> 2KCl + BaSO4
The net ionic equation for sodium acetate (NaC2H3O2) and barium sulfide (BaS) is: Ba2+(aq) + 2CH3COO-(aq) -> Ba(CH3COO)2(s) This equation shows the formation of insoluble barium acetate precipitate.
The balanced equation is: K2CO3(aq) + BaCl2(aq) -> 2KCl(aq) + BaCO3(s).
The balanced chemical equation for the reaction between aqueous ammonium sulfate (NH4)2SO4 and aqueous barium acetate Ba(C2H3O2)2 is: (NH4)2SO4 + Ba(C2H3O2)2 → BaSO4 + 2NH4C2H3O2. In this reaction, a white precipitate of barium sulfate (BaSO4) is formed.
The balanced equation for barium peroxide is: BaO2 -> BaO + 1/2 O2
The reaction is:Ba(NO3)2 + K2C2O4 = BaC2O4(s) + 2 KNO3
The balanced chemical equation for the reaction between barium nitrate (Ba(NO3)2) and potassium hydroxide (KOH) is: Ba(NO3)2 + 2KOH -> Ba(OH)2 + 2KNO3
2Na3(po4)(aq) +3Ba(C2H3O2)2(AQ)=Ba3(Po4)2(s) + 6NaO2C2H3(aq)
The net ionic equation for barium chloride (BaCl2) and lead acetate (Pb(C2H3O2)2) is Ba²⁺ + 2C2H3O2⁻ → Ba(C2H3O2)2. This equation represents the formation of barium acetate as a solid precipitate when barium chloride and lead acetate are mixed together.