Pb2+ + I- --> PbI2(s)
potassium and acetate ions are left out of the equation, because they don't react (stay unchanged in solution)
The net ionic equation for sodium acetate (NaCH3COO) and potassium nitrate (KNO3) is: CH3COO^- + K^+ -> KCH3COO
The molecular equation for lead(II) acetate reacting with potassium chromate is: Pb(C2H3O2)2 + K2CrO4 -> PbCrO4 + 2KCH3COO
The net ionic equation for the reaction of potassium chloride and lead (II) acetate is: Pb^2+ (aq) + 2Cl^- (aq) -> PbCl2 (s)
The formula for potassium sulphite is K2SO3.
KC2H3O2 potassium has a +1 charge Acetate ion has a -1 charge
The balanced chemical equation for the reaction between barium acetate and potassium iodide is: Ba(CH3COO)2 + 2KI -> BaI2 + 2KCH3COO
The preparation equation depends on the route by which this compound is prepared. A simple route is neutralization of acetic acid with potassium hydroxide: KOH + CH3COOH --> H2O + K+CH3COO-
Al(C2H3O2)3 + K3PO4 ==> AlPO4 + 3 C2H3O2Kor looked at another way... Al(CH3COO)3 + K3PO4 ==> AlPO4 + 3 CH3COOK
The reaction between potassium phosphate (K3PO4) and barium acetate (Ba(C2H3O2)2) will produce barium phosphate (Ba3(PO4)2) and potassium acetate (KCH3COO). The balanced chemical equation for this reaction is 3K3PO4 + Ba(C2H3O2)2 -> Ba3(PO4)2 + 6KCH3COO.
The balanced chemical equation for acetic acid (HC2H3O2) in vinegar reacting with potassium hydroxide (KOH) is: HC2H3O2 + KOH -> KC2H3O2 + H2O This balanced equation shows that one molecule of acetic acid reacts with one molecule of potassium hydroxide to form one molecule of potassium acetate and one molecule of water.
The balanced molecular equation for the reaction between sodium acetate (NaC2H3O2) and silver nitrate (AgNO3) is: 2NaC2H3O2 + AgNO3 -> 2AgC2H3O2 + NaNO3
When potassium metal (K) is added to a solution of barium acetate (Ba(C₂H₃O₂)₂), a single displacement reaction occurs. The balanced formula equation for this reaction is: [ 2 \text{K} + \text{Ba(C}_2\text{H}_3\text{O}_2\text{)}_2 \rightarrow \text{Ba} + 2 \text{KC}_2\text{H}_3\text{O}_2. ] In this reaction, potassium displaces barium, forming barium metal and potassium acetate.
The net ionic equation for sodium acetate (NaCH3COO) and potassium nitrate (KNO3) is: CH3COO^- + K^+ -> KCH3COO
The molecular equation for lead(II) acetate reacting with potassium chromate is: Pb(C2H3O2)2 + K2CrO4 -> PbCrO4 + 2KCH3COO
The balanced chemical equation for neutralizing aqueous acetic acid (HC2H3O2) with aqueous potassium hydroxide (KOH) is: HC2H3O2 + KOH → KC2H3O2 + H2O This reaction forms potassium acetate (KC2H3O2) and water (H2O) when acetic acid reacts with potassium hydroxide in a 1:1 molar ratio.
2CH3COONa+H2SO4 ---> 2CH3COOH+Na2SO4
The net ionic equation for the reaction of potassium chloride and lead (II) acetate is: Pb^2+ (aq) + 2Cl^- (aq) -> PbCl2 (s)