First, the decomposition of Ammonium Nitrate or NH4NO3 breaks down with heat into Nitrous Oxide (aka laughing gas) or simply N20 with the addition of H2O.
So I'm not sure if trying to balance NH4NO3->H2O+N2+O2 makes sense.
Instead I would suspect,
NH4NO3 (s) → 2 H2O (g) + N2O (g) to be your answer.
The balanced equation is as follows:
2NaNO3 -->2NaNO2 + O2
The balanced equation is 4 NH3 + 5 O2 = 4 NO + 6 H2O
Use whole number coefficients until you have the same number of atoms of each element on either side of the arrow.
2N2 + 5O2 --> 2N2O5
2(N2O)+3(O2)=4(NO2)
N2h4 + 2h2o2 = n2 + 4h2o
1 n2 + 2 o2 -> 1 n2o4
NO3 + H2O = HNO3 + OH ..correct?
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
Cu + 4HNO3 ----->Cu(NO3)2 + 2NO2 + 2H20
4(NH3) + 5(O2) --> 4NO + 6(H20)
Hno3 -----------h+ + (no3)-1
The equation is:H+ + (NO3)- + Na+ + (OH)- = (NO3)- + Na+ + H2O (2 H+ OH-)
Cu + HNO3 = Cu(NO3)2 + NO + H2O
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
Cu + 4HNO3 ----->Cu(NO3)2 + 2NO2 + 2H20
4(NH3) + 5(O2) --> 4NO + 6(H20)
Hno3 -----------h+ + (no3)-1
The equation is:H+ + (NO3)- + Na+ + (OH)- = (NO3)- + Na+ + H2O (2 H+ OH-)
HNO3 + H2O -> H3O + NO3 is very acidic. This is because HNO3 is a strong acid and almost completely dissociates in water
2 HNO3 + CuCO3 --> H2O + CO2 + Cu(NO3)2
IN this reaction the conjugate base is the nitrate ion, NO3-
What is the balanced equation for the reaction of calcuim hydroxide and nitric acid? . Ca(OH)2 .+..HNO3..=..Ca+2(NO3-1)..+.. H+1OH-1 (water) . Balance charges Ca(OH)2 .+..HNO3..=..Ca(NO3)2..+.. HOH .balance atoms Ca(OH)2… +…HNO3....=..Ca(NO3)2..+.. HOH Balance OH's Ca(OH)2….+.. HNO3….=.. Ca(NO3)2..+..2HOH . Balance H's Ca(OH)2….+..2HNO3..=.. Ca(NO3)2..+..2HOH . Done!!
The equation is: Zn + 2HNO3 -----> Zn(NO3)2 + H2
HNO3 + MgCO3 --> H2O + CO2 + Mg(NO3)2 (Products are water, carbon dioxide and magnesium nitrate)