Q: How do you beat stage 12 in hooda what 3?

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four monthsYes, Year 3 is Key Stage 2, Key Stage 1 is Years Reception to 2, Key Stage 3 is year 3 to 6, Key Stage 3 is year 7 to 9, Key Stage 4 is Years 10 and 11, and 6th Form is Year 12 and 13. Hope this Helps!

12+3(y) 12+ 3(-3) 12 + {3x (-3)} 12+ (-9) 12-9 3

3 - (-12) = 3 + 12 = 15.

√12 = √3 × √4 = 2√3 √12 × 3 = 6√3 √12 × 3 ≈ 10.4

I am going to guess that you mean: Find t when (√(t + 12)) - t = 0. Then, √(t + 12) = t; t + 12 = t²; (squaring both sides) t² - t - 12 = 0; (t - 4)(t + 3) = 0; and t = 4 or -3. We'd best check both results, because we squared both sides at an earlier stage, which introduces an ambiguity and, probably, an extraneous answer: Our original equation is seen to hold, for t = 4: √(4 + 12)) - 4 = √16 - 4 = 4 - 4 = 0. However, it does not hold, for t = -3. √(-3 + 12)) + 3 = √9 + 3 = 3 + 3 = 6 ≠ 0. Thus, the answer is that t = 4.

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