Let's take an example.
Suppose that the intermediate frequency is 10,7 MHz (FM).
The local oscillator works on 110,7 MHz.
First case: You receive a signal of 100 MHz, the mixer will generate a frequency of 110,7 + 100 = 210,7 MHz, which will be rejected by the band-pass filter. The difference of the two frequencies is 110,7 - 100 = 10,7 MHz (desired one).
Second case: You receive a signal of 121,4 MHz. The sum of that frequency and the local oscillator is 232,1 MHz, which will be rejected. The difference is 121,4 - 110,7 = 10,7 MHz. So the image frequency in that case is going to be 121,4 MHz.
Frequency = 1 / period of time.
period = 1 / frequency
f (image) = 2 * f (local oscillator) + fc ................. if f ( l.o ) > fc f (image) = 2* f (local oscillator) - fc
c=frequency x wavelength
Wavelength = (speed of the wave) divided by (frequency)
Assuming that the receiver uses a high-side local oscillator and an IF of 455 KHz, the image frequency is 910 KHz above. When tuned to 1600 KHz, the image frequency would be 2,510 KHz.
There are several ways to calculate the frequency of light emitted or absorbed by different chemicals, and they depend on what you already know. For example, if you know the energy of the particle, then you can calculate frequency from E = planck's constant x frequency and solve for frequency. If you happen to know the wavelength, then you can use C = wavelength x frequency and solve for frequency (where C = speed of light).
Amplitude doesn't depend on frequency or wavelength, so even if you know them, you have no way to calculate amplitude.
speed=frequency x wavelenth xD
If=lo-rf
period
To find (wavelength): Divide (speed) by (frequency). To find (frequency): Divide (speed) by (wavelength).
To calculate the frequency density we will simply divide the frequency by the class width.
The period is the reciprocal of the frequency, in other words, one divide by the frequency. If the frequency is in Hertz, the period is in seconds.