I would need more information, it depends on what you are given
Possibility 1:
force x mass = acceleration, so mass = acceleration/force
Possibility 2
density = mass/volume, so mass = density x volume
Possibility 3
momentum = mass x velocity, so mass = momentum/velocity
The molecular mass is the sum of the atomic weights of the elements contained in the molecule.
Ex.: mass of sodium chloride (NaCl) = atomic weight of Na + atomic weight of Cl
The mass of 3 mol of ammonia is 51,093 g; the number of ammonia molecules in 3 moles is18,066422571.10e23.
36amu
The answer is 9,3945.1023 molecules.
The same way you calculate the atomic mass of other elements.
To calculate the atomic mass of any element, add the no. of protons and neutrons. There sum will be the atomic mass. The mass of electrons is not counted towards the atomic mass.
The mass of 3 mol of ammonia is 51,093 g; the number of ammonia molecules in 3 moles is18,066422571.10e23.
The mass of 5 mol of ammonia is 85,155 g; the number of ammonia molecules in 5 moles is3,011 070 428 5.10e24.
Calculate volume of molecule, calculate mass of molecule, compare to bulk density. Lower bulk density indicates empty space.
- calculate the molecular mass of the substance from the atomic weights of the contained elements - 1 molecule gram of any substance contain 6,023 141 79.1023 molecules (Avogadro number) - mass of a single molecule is: Molecular mass in grams/Avogadro number
Molecules are not a force, they have mass.
36amu
To calculate the atomic mass of an element, add up the mass of protons and nuetrons.
No. you will know the volume of the unknown mass after you calculate the mass of ca0
The answer is 9,3945.1023 molecules.
The actual yield is given within the worded problem. The theoretical yield however is to be found. In order to calculate the theoretical yield, you need to convert the mass of the limiting reagent (LR) to the mass of the reagent in excess (ER). To find the limiting reagent, you need to first convert the mass of the limiting reagent to the mass of the reagent in excess (to find the theoretical yield)A. Convert mass of limiting reagent to mass reagent in excess (mass --> mass); in other words, find the mass of the reagent consumed.1. Multiply the mass of the limiting reagent by the # molecules of the reagent in excess and its molar mass.2. Divide the above by the # of molecules LR which is multiplied by its molar mass.Mass LR x # molecules ER x molar mass ER-- # molecules LR x molar mass LR3. Subtract the original mass of reagent in excess and the consumed reagent in excess.Original mass Reagent in Excess - Consumed Reagent in Excess= Reagent leftover/unused (theoretical yield).B. Find the percent yield of the product.--- Actual YieldTheoretical Yield x 100%
You can convert molecules to mass easily using the fact that there are 6.022*10^23 molecules in a mole of an substance. Convert your molecules to moles, then use the molar mass of your substance to determine the mass.
The same way you calculate the atomic mass of other elements.