Very basically, simply divide the voltage by the amperage. Thsi is not for calculating Ohms of resistance, just Ohms. For example, a 9 volt battery that delivers 3 amps has 3 ohms.
To calculate ohms of resistance we use the ohms law. This measures the difference in current flow in amps (amps/current is amount or volume of flow, volts is power pushing that current, sort of) and voltage. For instance, measure the amps and voltage at the source and record the ohms. Then record the same at the end point the difference in ohms is ohms of resistance. So, if we measure 10 volts and 2 amps at the source we have 5 ohms. at the end point we have 8 volts and 1 amp we have 8 ohms. therefore we have 13 ohms of resistance.
1
Determine current. Current is the flow of electricity measured in amps. For example a current has four amps in the circuit.
2
Determine voltage. Voltage is the difference in electrical potential from two points, measured in volts. For example, there is two-hundred volts in a circuit.
3
Divide voltage by current to calculate resistance. Resistance is measured in ohms. In the example, two-hundred volts divided by four amps equals fifty ohms.
4
To get ohms of resistance, measure the end point. at the endpoint we have 100 volts and 2 amps=50 ohms. therefore we have 100 ohms of resistance
ohms law.
Ohm's Law requires you know two of three parameters to calculate the third. Volts = Amps x Ohms You need to know current flowing through resistance to calculate voltage drop.
The normal calculations for watts are as follows.amps x volts = wattsvolts2 / ohms = wattsamps2 x ohms = wattsScroll down to the Related links and look at "Watts, Volts, Amperes, and Ohms".
If wired in parallel then 4 ohms.
Ohm's laws says it will be 1.5 vdc divided by 330 ohms.
No, they are different things. This would be like calculating an apple into an orange.
The resistance R in ohms (Ω) is equal to the voltage V in volts (V) divided by the current I in amps (A)
Ohm's Law.
9 amperes.
Ohm's law: Voltage is resistance times current. 80 ohms time 0.5 amperes = 40 volts.
To calculate the current in the parallel circuit we need the concept of ohms law, V=IR we know the resistance, R=48 ohms voltage will be constant as 220-230 volts so, I= V/R = 230/48 = 4.791 A Add currents of three lamps, ie., I = 14.375
V = I.R R = V/I R = 110/0.5 R = 220 Ohms