When a cold object and a hot object are in direct contact (touching) heat will be transferred through thermal conduction.
Normally, heat transfer processes are categorized as thermal conduction, radiative transfer or convection.
Heat transfer through thermal conduction is the direct transfer of kinetic energy from one molecule to the nearby molecules. Because temperature is directly proportional to kinetic energy, interactions between neighboring particles exchange energy and that exchange energy gradually works it way from the higher temperature regions to the lower temperature regions. The process of the temperature becoming the same is called thermal equilibration.
Convective heat transfer occurs in fluids. If a gas, liquid, or other fluid, changes in fluid density change the buoyancy and will cause fluid to flow (a process called convection) and the heat contained in the warmer fluid is transferred to a new location by the physical movement of the fluid.
Radiative transfer occurs when a hot object radiates electromagnetic energy. While the sun is an obvious source of electromagnetic energy, it is also generated in smaller amounts by any object. The hotter objects radiate more electromagnetic energy and the cooler objects absorb it. This radiative transfer is important but not as noticeable usually as the other two. It does occur between objects whether they are in direct contact or not, but is usually so small as not to be important of the objects are touching.
The heat gain or loss in a fluid is [(the temperature rise or fall) x (fluid flow per second) x (specific heat capacity of the fluid)]. So if you can measure these quantities for both fluids, they should be equal apart from any losses to the surroundings.
The equation for the overall heat transfer coefficient of a shell and tube heat exchanger is:
1/U = 1/hi + Rfi + Rfo + Rw + 1/ho
Where
U= overall heat transfer coefficient
hi= inside convective heat transfer coefficient, determined by correlations
Rfi= inside fouling resistance, assume a value or tabulated in a text
Rfo= outside fouling resistance, assume a value or tabulated in a text (often neglected)
Rw= conductive resistance of the wall = ln(ro/ri)/kw
kw= thermal conductivity of the wall material, tabulated in a text
ro= inside radius
ri= outside radius
ho= outside convective heat transfer coefficient, determined by correlations
That very easy matter... u should find whether the modes of transfer... after finding modes u should find laminar or turblnt... & u should also find surface type of fow... then go to data book.. u ill get it
it is ratio of the total heat transfer from the surface area associated with both the fins and exposed portion of the base to maximum heat transfer from same surface area (in ideal conditions we get maximum heat transfer)
You calculate overall percentage of engineering marks by taking the number of engineering marks and dividing it by the percentage. When you do that, you will get your average percentage of engineering marks.
FTP is the File Transfer Protocol, which can be used to transmit computer files from one computer to another. The files that are transmitted may contain any type of data, including executable machine code files. Typically, the files are compressed archives (such as ZIP or RAR files) to reduce the overall transmission times.
Yes
More than on your state rank, it depends on your overall rank. You need a good overall rank to get admission in Murthal Engg. college
I have a book (Introduction to heat transfer - Bergmann), there is an example of an oil cooler cooled by air (crossflow heat exchanger with both fluids unmixed). There is written: "... with an overall heat transfer coefficient of 53 W/(m²*K)."
The equation for the duty of a heat exchanger is:Q=U*A*LMTDwhere:Q is the dutyA is the overall heat transfer areaLMTD is the log mean temperature difference.generally when desiging heat exchangers the desired duty is known, as are the desired inlet and outlet temperatures. Therefore we solve for A to find the overall heat transfer area.A= Q/(U*A*LMTD)If we hold Q and the LMTD constant, you can see that a larger overall heat transfer coefficient U, will result in a small exchanger area and, therefore; a smaller, less expensive piece of equipment.The the greater the U, the better the performance.
Yes, the juice temperature increases with an increasing convective heat transfer coefficient at any constant kettle surface temperature. The convective heat transfer coefficient represents the efficiency of heat transfer from the kettle to the juice. As the convective heat transfer coefficient rises, more heat is transferred from the kettle surface to the juice per unit of time. This increased efficiency results in a faster temperature rise in the juice. Therefore, a higher convective heat transfer coefficient enhances the overall heating process, leading to a greater temperature increase in the juice even when the kettle surface temperature remains constant.
AdvantagesEfficient use of Temperature DifferenceThe fully countercurrent system(TYPE-1) is able to exchange heat even if temperature difference is extremely close. Most effective saving energy is possible.Low Fouling (Self Cleaning)The rotary current of spiral heat exchanger possesses the property of scraping off and spilling the dirty sedimentation(stagnation solid). Even though scales adhere to it, the cross-section of the adherent part becomes smaller, the flow-speed would be quickly and bring the function of self cleaning by single-pass flow.High Overall Heat Transfer CoefficientSpiral flow passage easily creates turbulent flow.Optimum flow speed can be gained by selecting the most suitable spiral channel. High Overall Heat Transfer Coefficient can be achieved.Easy MaintenanceThe heat transfer part is easily accessed and checked. It is possible to easily do by removing the cover of the both ends, for the inspection of the inside.The maintenance cost of Spiral Heat Exchanger is much lower than others.Space SavingSHE equipment volume is far compact comparing to Tubular Heat Exchanger. Plant space can be saved and plant initial cost can be saved.
conduction
Conduction
A coefficient of correlation of 0.70 infers that there is an overall correlation between the trends being compared. The correlation is not perfect, but enough to be acknowledged and researched further.
it is grades
the transfer of heat through empty space is called RADIATION.
No. Cooling the compressor will do little to improve the efficiency of the system. The compressor will be slightly more efficient, but the overall efficiency of the heat transfer will be unchanged. Cooling the condenser (the outside heat exchanger coils) will do more, but the money saved in AC costs will be offset by water wasted. Also, keep in mind the heat exchanger outside is an electrical device. It is designed to withstand rain on it, not water being hosed in it. Be carefull. This idea is half-cocked and I would not recommend it.
Calculate the % yield of each step, and then multiply them together. e.g. if all steps have 50% yield then Overall yield = (50/100)6 = 1.5%
They transfer energy as heat from equatorial regions to high latitudes