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How do you calculate the acceleration of a 2 kg block on a horizontal friction-free air table when you exert a horizontal net force of 20 N?
Wiki User
∙ 10y ago
2,000 grams.
Wiki User
∙ 14y ago
You can calculate the acceleration of the block using Newton's second law, which states that acceleration is directly proportional to the net force applied and inversely proportional to the mass of the object. In this case, acceleration = net force / mass, so acceleration = 20 N / 2 kg = 10 m/s^2.
Wiki User
∙ 10y agof / m = (15 N) / (2.5 kg) = 6 m/s^2
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How would the block's acceleration change if you doubled the mass of the block but kept the rocket's force the same Explain your answer.?
If you double the mass of the block but keep the rocket's force the same, the acceleration of the block would decrease. This is because acceleration is inversely proportional to mass according to Newton's second law of motion (F = ma). With twice the mass, the same force will result in a lower acceleration.
How would the observed value of the acceleration of a block be affected if the one used is heavier?
If a heavier block is used, the observed acceleration would likely decrease. This is because a heavier block has more mass and requires more force to accelerate. Therefore, the force applied would need to overcome the increased inertia of the heavier block, resulting in a lower observed acceleration.
What is the acceleration of a 38 kg block of cement when pulled sideways with a net force of 245 N?
The acceleration of the block can be calculated using Newton's Second Law: F = ma, where F is the net force, m is the mass of the block, and a is the acceleration. Rearranging the formula to solve for acceleration gives a = F/m. Plugging in the values F = 245 N and m = 38 kg, the acceleration would be 6.45 m/s^2.
A 50kg block of cement is pulled upward with a force of 600NWhat is its acceleration?
Using Newton's second law (F=ma), the acceleration can be calculated by dividing the force applied by the mass of the block. Therefore, the acceleration of the 50kg block under a 600N force is 600N / 50kg = 12 m/s^2.
Horizontal force required to pull 75 kg block?
To pull a 75 kg block horizontally, you need to overcome the force of static friction between the block and the surface it's on. The force required would depend on the coefficient of static friction between the block and the surface. You can calculate it using the formula: Force of friction = coefficient of static friction × normal force.
What is the acceleration of a 37kg block when pulled by a force of 170 N?
Using the equation F = ma, where F is the force applied (170 N), m is the mass of the block (37 kg), and a is the acceleration, we can solve for a. Rearranging the equation gives a = F/m = 170 N / 37 kg ≈ 4.59 m/s^2. Hence, the acceleration of the 37 kg block when pulled by a force of 170 N is approximately 4.59 m/s^2.
What is the acceleration of a 38 kg block of cement when pulled sideways with a net force of 245 N?
The acceleration of the block can be calculated using Newton's Second Law: F = ma, where F is the net force, m is the mass of the block, and a is the acceleration. Rearranging the formula to solve for acceleration gives a = F/m. Plugging in the values F = 245 N and m = 38 kg, the acceleration would be 6.45 m/s^2.
A 50kg block of cement is pulled upward with a force of 600NWhat is its acceleration?
Using Newton's second law (F=ma), the acceleration can be calculated by dividing the force applied by the mass of the block. Therefore, the acceleration of the 50kg block under a 600N force is 600N / 50kg = 12 m/s^2.
How would the observed value of the acceleration of a block be affected if the one used is heavier?
If a heavier block is used, the observed acceleration would likely decrease. This is because a heavier block has more mass and requires more force to accelerate. Therefore, the force applied would need to overcome the increased inertia of the heavier block, resulting in a lower observed acceleration.
How do you calculate gross block?
76.95
Horizontal force required to pull 75 kg block?
To pull a 75 kg block horizontally, you need to overcome the force of static friction between the block and the surface it's on. The force required would depend on the coefficient of static friction between the block and the surface. You can calculate it using the formula: Force of friction = coefficient of static friction × normal force.
What would win in a race a truck with a 454 big block or a 350 small block?
The 454 it would have better acceleration
How much work is required to lift a 3.7kg concrete block to a height of 2.2 m?
The work required to lift the concrete block can be calculated using the formula: Work = force x distance. First, you need to calculate the force required to lift the block, which is equal to the weight of the block multiplied by the acceleration due to gravity (9.81 m/s^2). Then, multiply the force by the distance lifted (2.2 m) to find the work done.
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What is the mass of the 20 N block?
The mass of the block can be calculated using the formula: mass = weight / acceleration due to gravity. Since weight = 20 N and acceleration due to gravity is typically taken as 9.81 m/s^2, the mass of the block would be approximately 2.04 kg.
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What happens when you put a negative acceleration and positive acceleration together?
When you combine a negative acceleration (deceleration) with a positive acceleration (acceleration), their effects add up algebraically. This means that the resulting acceleration will depend on the magnitudes of the two accelerations and their directions. If the positive acceleration is greater than the negative acceleration, the object will still be accelerating in the positive direction. If the negative acceleration is greater, the object will eventually decelerate and change direction.
