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How do you calculate the acceleration of a 2 kg block on a horizontal friction-free air table when you exert a horizontal net force of 20 N?
Wiki User
∙ 10y ago
2,000 grams.
Wiki User
∙ 14y ago
Wiki User
∙ 10y agof / m = (15 N) / (2.5 kg) = 6 m/s^2
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How would the observed value of the acceleration of a block be affected if the one used is heavier?
From f = m*a, a = f/m, so if the force remains constant and the mass increases, the acceleration will decrease. But if the block is on an incline and the force is provided by gravity, the force will increase directly proportional to the mass of the block, and acceleration will remain the same.
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You add them. For example, if a block is accelerating to the right at 2 m/s2 but is being slowed by friction accelerating the block to the left at 1 m/s2, then you can add the accelerations--positive is right and negative is left. The net acceleration would be 1 m/s2 to the right.
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A 500g block of ice weighs approx. 4.905 Newtons as weight is the force due to gravitational acceleration acting on a mass.F=mgwhere:F = force (Newtons)Am = mass (kg)g = gravitational acceleration (ms-2)BA In this case the force is due to gravitational acceleration and is therefore weight.B g is assumed to equal 9.81ms-2.
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How would the observed value of the acceleration of a block be affected if the one used is heavier?
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What happens when you put a negative acceleration and positive acceleration together?
You add them. For example, if a block is accelerating to the right at 2 m/s2 but is being slowed by friction accelerating the block to the left at 1 m/s2, then you can add the accelerations--positive is right and negative is left. The net acceleration would be 1 m/s2 to the right.
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the work performed is the weight of the block times the height, or rise, of the incline
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