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That's old-fashioned nomenclature, but that's okay - the "-ic" suffix means you're dealing with tin with a higher number of valence electrons, in this case, 4. So with tin as +4 and oxygen, as always, as -2, you're going to get a formula of SnO2. Tin with a charge of +2 is the other possible valence option, and that's called "stannous oxide" with the "-ous" suffix, and a formula of SnO. The better way to express stannic oxide is simply to say tin(IV) oxide, and stannous oxide as tin(II) oxide.

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Q: How do you calculate the chemical formulae of stannic oxide?
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