Voltage x Current = Power
So Power / voltage = current
Now you do the math
To limit the current through the lamp when the gas ionises and conducts.
mathercode
Measure the outer diameter of the tube and its' length. Calculate each tube volume and multiply by number of tubes. For those who want to calculate the inside liquid capacity of the shell side, it is advise to include the baffle volume with the tube bundle volume.
A choke coil, also known as a ballast, limits the current to a fluorescent tube by providing a high impedance to the flow of current. This high impedance restricts the current flowing through the tube, allowing it to operate within its required current range. The choke coil also helps regulate the starting voltage and stabilize the operation of the tube.
by u tube manometer
power is = V2/R so 40x40= (230)2/R R= 33.25 now V= IR where I is current 230= IXR I= 230/33.25 = 6.9 amp
A starter initially provides a path to complete the circuit. The tube light starts when the current flows through the ionized gas in the main tube. woodenboatusa.com
The electrons in the mercury arc current in the tube causes the mercury vapor to emit ultraviolet light. The inside surface of the tube is coated with a phosphor that glows with visible light when hit by ultraviolet light.
tube light woks like a tube light....
tube light woks like a tube light....
"Normal" light globes use a glowing filament, heated by the current. Flourescent tubes ignite a gas within a tube, using an arc.
http://en.wikipedia.org/wiki/Fluorescent_lamp
To limit the current through the lamp when the gas ionises and conducts.
mathercode
tube light
tube light
tube light