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The answer that the homework assigned wanted was (580 cal/g)(400g) = 232,000 cal = 971,105.60 J Heat Transfer equation: q=mc(dT) Energy = (mass) x (specific heat) x (change in temp) m = 400 grams c (of H20) = 4.186 Joules/gram (you just look up this value) dT = 100°C-25°C (assume water evaporates at 100°C, so change in temp is T(final) - T(initial) q = 400g x 4.186J/g x 75°C q= 125,580 J = 125.6 KJ

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Q: How do you calculate the heat required to evaporate 400 g of water at 25 degrees Celsius?
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