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Water
q = mC∆T214 cal = (10g)(1cal/g/deg)(∆T)∆T = 214 cal/(10g)(1cal/g/deg) = 21.4 degreesSo, the temperature of the water will increase by 21.4 degrees
10g = 10ml of water, other liquids may vary
You need to know the molar mass of NaCl. Then 10g/molar mass = moles.
Helium is helium. Storing it is difficult as it diffuses through many substances.
Water
convert the .2 kg of NaCl to moles of NaCl.
q = mC∆T214 cal = (10g)(1cal/g/deg)(∆T)∆T = 214 cal/(10g)(1cal/g/deg) = 21.4 degreesSo, the temperature of the water will increase by 21.4 degrees
10g of jelly beans
+10g
10g-g = 9g
10g stands for 10 grams.
Density is just mass per volume (usually g/mL). Take the specified mass, and then just divide it by the specified volume. For example, if you have 10g of a liquid with volume of 5mL, its density is (10g)/(5mL) = 2g/mL.
10g = 10ml of water, other liquids may vary
20%
There are one hundred 10g in 1kilo
20 x 500 mg = 10g or 10g = 500mg x 20