Using one of the formulae for constant acceleration: vf2 = vi2 + 2as, where vf is the final velocity, vi is the initial velocity (omit this term in this case, since the initial velocity is zero), a is the acceleration (9.8 in this case), and s is the distance.
That is just not true! If you can calculate its average speed you should be able to calculate its speed at any point in time during its flight, including its final velocity.
They will fall at the same speed. See Galileo.
iT DEPENDS IF THE BALL IS LIGHT THE LIGTER MOSTLIKLEY TO HAVE THE SAME SPEED.
They will fall at the same speed once they reach terminal velocity.
they both fall at the same rate of speed.
They would fall at the same speed - in a vacuum.
Because the ball and the cart are moving at the same forward speed.
they would both fall at the same speed
With air resistance, the ping pong ball. Without air resistance (e.g., on the Moon), both fall at the same speed.
All will fall at the same speed in vacuum because there will be no air resistance. The gravity will pull all objects in the same force.
Because both You and the ball (and everything else in the cabin for that sake) are moving with the same speed as the car :)
It depends on the time of fall or the distance of fall: Vb = g*t or Vb = √(2*g*y) where y is the distance fallen